Answer:
You are correct, it is (3) the ball is in motion as it rolls down the slope.
Explanation:
For number 1 it would make sense because how would the student be in motion if he is just standing there throwing the ball down the slope, not himself.
For number 2 still wouldn't make so much sense since we are talking about the ball being in motion not the student.
For number 3 it seems the most reasonable because the ball is in motion as it is rolling down the slope.
For number 4 it doesn't make sense for a ball to lose its shape just by rolling, also even if you're like: "oh, but what if its leaking air or has a hole??" well easy then. It STILL wouldn't matter because in the sentence it never specifies it has a "hole" or is "leaking air" therefore this answer is wrong.
YOUR ANSWER IS number 3.
homo. It is a mixture because it has different things in it. If they are distributed homogeneously ...
Answer:
Acceleration of the train is -3 m/s²
Explanation:
Since it stops,
final velocity (v) = 0 m/s
time (t) = 25 seconds
initial velocity(u) = 75 m/s
Now,
accelereation = (v-u)/t
or, a = (0-75)/25
or, a = -75/25
so, a = -3 m/s²
Answer:
3 Cycles
Explanation:
Every cycle on a cosine function are marked by the completion of 5 key points when moving along the x-axis:
(5, 0, -5, 0, 5)
This cycle has a frequency of 2, occurring once every second, thus answering our question easily.
The terminal velocity as it falls through still air is 4.65154 in/s.
The diameter of small water droplet is 1.25 mil= 1.25×0.0254×10^-3 m
= 3.175 × 10^-5 m
Now the viscosity of still air is η = 1.83× 10⁻⁵ Pa
So the formula for drag force is:
Fd = 6πηrv
where, v is the velocity.
Now to attain terminal velocity acceleration must be zero.
→ W = Fd
ρVg = 6πrηv
ρ × 4/3 πr³×g = 6πrηv
v = 2/9 × ρgr³/ η
v = 2/9 × 10³×9.81×(3.175×10^-3) / 18.6×10^-6
v = 0.1181 m/s
v = 4.65154 in/s
Learn more about terminal velocity here:
brainly.com/question/20409472
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