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Harlamova29_29 [7]
3 years ago
15

What is the difference between output and input forces

Physics
1 answer:
seropon [69]3 years ago
7 0

Output Force- the force exerted on an object by a simple machine

Input Force-  the initial force used to get a machine to begin working.

Input Force represents the amount of force that you put into another object. Output Force represents the force that a specific object has as a result of the input force.

- Hope this Helps :)

You might be interested in
4. A steel cable spanning a river is 220.000 m long when the temperature is 30.°C.
romanna [79]

Answer:

219.9208  m

Explanation:

The new length is given by

New length= Original length *(1-Temperature change*coefficient of

thermal expansion of steel)

Here, the change in temperature is 30^{\circ}-0^{\circ}= 30^{\circ}

New length= 220.000(1-30*12x10^{-6}=219.9208m

Therefore, the new length will be 219.9208 m

5 0
3 years ago
Four identical capacitors are connected with a resistor in two different ways. When they are connected as in part a of the drawi
Nina [5.8K]

Answer:

T_2 = 0.592

Explanation:

Given

T_1 = 1.48s

See attachment for connection

Required

Determine the time constant in (b)

First, we calculate the total capacitance (C1) in (a):

The upper two connections are connected serially:

So, we have:

\frac{1}{C_{up}} = \frac{1}{C} + \frac{1}{C}

Take LCM

\frac{1}{C_{up}} = \frac{1+1}{C}

\frac{1}{C_{up}}= \frac{2}{C}

Cross Multiply

C_{up} * 2 = C * 1

C_{up} * 2 = C

Make C_{up} the subject

C_{up} = \frac{1}{2}C

The bottom two are also connected serially.

In other words, the upper and the bottom have the same capacitance.

So, the total (C) is:

C_1 = 2 * C_{up}

C_1 = 2 * \frac{1}{2}C

C_1 = C

The total capacitance in (b) is calculated as:

First, we calculate the parallel capacitance (Cp) is:

C_p = C+C

C_p = 2C

So, the total capacitance (C2) is:

\frac{1}{C_2} = \frac{1}{C_p} + \frac{1}{C} + \frac{1}{C}

\frac{1}{C_2} = \frac{1}{2C} + \frac{1}{C} + \frac{1}{C}

Take LCM

\frac{1}{C_2} = \frac{1 + 2 + 2}{2C}

\frac{1}{C_2} = \frac{5}{2C}

Inverse both sides

C_2 = \frac{2}{5}C

Both (a) and (b) have the same resistance.

So:

We have:

Time constant is directional proportional to capacitance:

So:

T\ \alpha\ C

Convert to equation

T\ =kC

Make k the subject

k = \frac{T}{C}

k = \frac{T_1}{C_1} = \frac{T_2}{C_2}

\frac{T_1}{C_1} = \frac{T_2}{C_2}

Make T2 the subject

T_2 = \frac{T_1 * C_2}{C_1}

Substitute values for T1, C1 and C2

T_2 = \frac{1.48 * \frac{2}{5}C}{C}

T_2 = \frac{1.48 * \frac{2}{5}}{1}

T_2 = \frac{0.592}{1}

T_2 = 0.592

Hence, the time constance of (b) is 0.592 s

8 0
2 years ago
An object has a mass of 0.250 kg. What is the gravitational force of on the object by the earth?
sesenic [268]

Answer:

2.4525 N

Explanation:

The earths gravity is 9.81 N/Kg

And so to work this out you would multiply 9.81 by 0.250 which equals to 2.4525N

7 0
3 years ago
A heater is being designed that uses a coil of 14-gauge nichrome wire to generate 300 W using a voltage of V = 110 V . How long
Mazyrski [523]

Answer:

The length of the wire is 83.2 m.

Explanation:

Given that,

Power of heater, P = 300 W

Voltage, V = 110 V

The resistivity of nichrome wire is, \rho=100\times 10^{-8}\ \Omega-m

The electric power of a wire is given by :

P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{(110)^2}{300}\\\\R=40.34\ \Omega

Area of cross section of the wire is :

A=\pi r^2\\\\A=\pi (0.000815)^2\\\\A=2.08\times 10^{-6}\ m^2

Resistance of a material is given by :

R=\rho \dfrac{L}{A}\\\\L=\dfrac{RA}{\rho}\\\\L=\dfrac{40\times 2.08\times 10^{-6}}{10^{-6}}\\\\L=83.2\ m

So, the length of the wire is 83.2 m. Hence, this is the required solution.

5 0
3 years ago
If the v – t graph of a particle is parallel to the t – axis the body has (a) uniform velocity (b) uniform acceleration (c) zero
maxonik [38]

Answer:

zero  velocity

Explanation:

if the v-t graph is parallel to the time axis its mean body has covered no path in other words the body is at rest so the velocity of the body should be zero

hope my answer will helps u plz mark me brainlist

5 0
3 years ago
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