a car with a mass of 1000-liogram accerlerates from rest, and travels a distanceof 48 meters druing its first 4.0 seconds of uni
1 answer:
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Explanation :
It is given that,
Mass of the car, m = 1000 kg
Force applied by the motor,
The static and dynamic friction coefficient is,
Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,
So, the acceleration of the car is . Hence, this is the required solution.
Answer:
The volume of the submerged part of her body is
Explanation:
Let's define the buoyant force acting on a submerged object.
In a submerged object acts a buoyant force which can be calculated as :
ρ.V.g
Where ''B'' is the buoyant force
Where ''ρ'' is the density of the fluid
Where ''V'' is the submerged volume of the object
Where ''g'' is the acceleration due to gravity
Because the girl is floating we can state that the weight of the girl is equal to the buoyant force.
We can write :
(I)
Where ''W'' is weight
⇒ If we consider ρ = (water density) and
and replacing this values in the equation (I) ⇒
ρ.V.g = 610N
(II)
The force unit ''N'' (Newton) is defined as
Using this in the equation (II) :
We find that the volume of the submerged part of her body is