784 Newton ( mass x gravity = 80 x 9.8)
A. The acceleration of the ball while it is in flight?
magnitude is 0 m/s² (magnitude is zero)
B. The velocity of the ball when it reaches its maximum height is 0 m/s (magnitude is zero)
C. The initial velocity of the ball 8.036 m/s upward
D. The maximum height reached by the ball is 3.29 m
<h3>A. How to determine the acceleration in the flight</h3>
Considering that the ball came to rest after 1.64s, it means the entire acceleration of the flight is zero as the ball was not moving in any form again.
<h3>B. How to determine the velocity at maximum height</h3>
At maximum height, the velocity of the ball is zero as it no longer has magnitude to keep going upwards. Hence the ball begins to ball down.
<h3>C. How to determine the initial velocity</h3>
- Acceleration due to gravity (g) = 9.8 m/s²
- Final velocity (v) = 0 m/s
- Time of flight (T) = 1.64 s
- Time to reach maximum height (t) = T / 2 = 1.64 / 2 = 0.82 s
- Initial velocity (u) =?
v = u - gt (since the ball is going against gravity)
0 = u - (9.8 × 0.82)
0 = u - 8.036
Collect like terms
u = 0 + 8.036
u = 8.036 m/s upward
<h3>D. How to determine the maximum height reached by the ball</h3>
- Time to reach maximum height (t) = T / 2 = 1.64 / 2 = 0.82 s
- Acceleration due to gravity (g) = 9.8 m/s²
- Maximum height (h)
h = ½gt²
h = ½ × 9.8 × 0.82²
h = 3.29 m
Learn more about motion under gravity:
brainly.com/question/20385439
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Answer:
The answer is C "think about the problem first, systematically consider all factors, and form a hypothesis"
Explanation:
In physics there is some basic fomula that sir Isacc Newton proposed under the topic of motion. The three formulas are below;
<em>1) v=u+at</em>
<em>2)v^2=u^2+2as</em>
<em>3)s=ut+(1/2)(at^2)</em>
the variables are explained below;
u= initial velocity of the body
a=acceleration/Speed of the body
t= time taken by the body while travelling
s= displacement of the body.
Therefore to solve keatons problem, the factors(variables) in the formulas above need to be systematically considered. Since the ball was dropped from the top of the building, the initial velocity is 0 because the body was at rest. Also the acceleration will be acceleration due to gravity (9.8m/s^2)
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