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Korolek [52]
3 years ago
7

Light can be made to have a higher intensity by raising its

Physics
1 answer:
e-lub [12.9K]3 years ago
3 0

Answer:

Frequency

Explanation:

The intensity of light is increased by increasing the number of photon per second, and the number of photon per second is referred to as frequency. A photon the smallest unit of light. If the frequency is increased, the number of photons per second increases hence an increase in intensity.

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A block of mass 500g is pulled from rest on ahorizontal frictionless bench by a steady force F and travels 8m in 2s find the acc
Korvikt [17]

<u>We are Given:</u>

Mass of the block (m) = 500 grams or 0.5 Kg

Initial velocity of the block (u) = 0 m/s

Distance travelled by the block (s) = 8 m

Time taken to cover 8 m (t)= 2 seconds

Acceleration of the block (a) = a m/s²

<u>Solving for the acceleration:</u>

From the seconds equation of motion:

s = ut + 1/2* (at²)

<em>replacing the variables</em>

8 = (0)(2) + 1/2(a)(2)²

8 = 2a

a = 4 m/s²

Therefore, the acceleration of the block is 4 m/s²

3 0
3 years ago
A snowball is rolling down a hill at 4.5 m/s and accumulating snow as it goes. Its diameter begins at 0.50 m and ends at the bot
Reil [10]
To find the change in centripetal acceleration, you should first look for the centripetal acceleration at the top of the hill and at the bottom of the hill.

The formula for centripetal acceleration is:
Centripetal Acceleration = v squared divided by r

where:
v = velocity, m/s
r= radium, m

assuming the velocity does not change:

at the top of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 0.25 m
                                      = 81 m/s^2

at the bottom of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 1.25 m
                                      = 16.2 m/s^2

to find the change in centripetal acceleration, take the difference of the two.
change in centripetal acceleration = centripetal acceleration at the top of the hill - centripetal acceleration at the bottom of the hill

= 81 m/s^2 - 16.2 m/s^2
= 64.8 m/s^2 or 65 m/s^2
6 0
4 years ago
A 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. What is the magnitude of the net force causing it t
weeeeeb [17]

The magnitude of the net force causing the 2300kg car to slow down is 6900N

HOW TO CALCULATE FORCE:

  • The net force applied on a moving object can be calculated by multiplying the mass of the object by its acceleration. That is;

  • Force (N) = mass (kg) × acceleration (m/s²)

  • According to this question, a 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. The net force causing the car to stop can be calculated as follows:

F = 2300kg × 3m/s²

F = 6900N

  • Therefore, the magnitude of the net force causing the 2300kg car to slow down is 6900N.

Learn more at: brainly.com/question/18109210?referrer=searchResults

4 0
3 years ago
This is for physical science i don't understand (please help) i need an answer by 11:40
coldgirl [10]

Answer: 1.4mi/hr²

Explanation:

Blank 1: We know that acceleration is the change in velocity/change in time

Using this, we know that the acceleration will be: (50-15)/25 = 1.4

Blank 2: mi/hr²

8 0
2 years ago
Which of the following is a force acting between objects that do not touch? Pls answer in 5-10 min!
lisabon 2012 [21]

Answer:

Electrical force

Explanation:

The electrons aren't actually touching each other. Normal is something on something pushed by gravity by they are touching, frictional is rubbing, applied is pushing

8 0
2 years ago
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