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2 years ago

Please hurry! classify the following as a

Chemistry

2 answers:

mafiozo [28]2 years ago

6 0

Answer:it’s A

Explanation:

Talja [164]2 years ago

5 0

Answer:

pure substance.

Explanation:

i hope that helps

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In a mixture of hydrogen and nitrogen gases, the mole fraction of nitrogen is 0.333. If the partial pressure of hydrogen in the

notka56 [123]

Answer:

$P_T=112.4torr$

Explanation:

Hello there!

In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:

$P_{H_2}=x_{H_2}*P_T$

And can be solved for the total pressure as follows:

$P_T=\frac{P_{H_2}}{x_{H_2}}$

However, we first calculate the mole fraction of hydrogen by subtracting that of nitrogen to 1 due to:

$x_{H_2}+x_{N_2}=1\\\\x_{H_2}=1-0.333=0.667$

Then, we can plug in to obtain the total pressure:

$P_T=\frac{75.0torr}{0.667}\\\\P_T=112.4torr$

Regards!

4 0

3 years ago

Argon (Ar) and helium (He) are initially in separate compartments of a container at 25°C. The

love history [14]

Answer:

(a) $V_B=11.68L$

(b) $x_{He}=0.533$

Explanation:

Hello,

In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:

$n_A=\frac{0.082\frac{atm*L}{mol*K}*298K}{1.974 atm*6.00L}=2.063mol$

Thus, since the final pressure is 3.60 bar, we can write:

$P=x_{Ar}P_A+x_{He}P_B\\\\P=\frac{n_{Ar}}{n_{Ar}+n_{He}} P_A+\frac{n_{He}}{n_{Ar}+n_{He}} P_B\\\\3.60bar=\frac{2.063mol}{2.063mol+n_{He}} *2.00bar+\frac{n_{He}}{2.063mol+n_{He}} *5.00bar$

The moles of helium could be computed via solver as:

$n_{He}=2.358mol$

Or algebraically:

$3.60bar=\frac{1}{2.063mol+n_{He}} *(4.0126+5.00*n_{He})\\\\7.314+3.60n_{He}=4.013+5.00*n_{He}\\\\7.314-4.013=5.00*n_{He}-3.60n_{He}\\\\n_{He}=\frac{3.3}{1.4}=2.358mol$

In such a way, the volume of the compartment B is:

$V_B=\frac{n_{He}RT}{P_B}=\frac{2.358mol*0.082\frac{atm*L}{mol*K}*298.15K}{4.935atm}\\ \\V_B=11.68L$

Finally, he mole fraction of He is:

$x_{He}=\frac{2.358}{2.358+2.063}\\ \\x_{He}=0.533$

Regards.

8 0

3 years ago

A chlorine atom has a diameter of 175 picometers (pm). Please write the diameter, in metered, in scientific notation.

IrinaVladis [17]

The answer is 1.75 x 10¹⁰ m.
Scientific notation<span> refers to a mathematical expression that is used to represent a decimal number between 1 and 10 multiplied by ten, or we can say that to write a large numbers using less digits.
Diameter of chlorine atom = </span><span>175 picometers (pm)
</span>175 pm = <span>0.000000000175 m
in scientific notation we will write </span>0.000000000175 m as <span>1.75 x 10</span>¹⁰ m

8 0

3 years ago

8. When rubidium and fluorine combine to produce the compound RbF, che ions

skelet666 [1.2K]

Answer:

The answer is C, both krypton and neon.

Explanation:

I got the answer wrong and my teacher told me that c is the right answer choice

8 0

3 years ago

How many moles of CO2 are there in 8.91 x 1023 molecules of CO2?<br> (1 mole= 6.02 x 1023)

Karo-lina-s [1.5K]

Answer:

<h2>1.48 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{8.91 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{8.91}{6.02} \\ = 1.480066...$

We have the final answer as

<h3>1.48 moles</h3>

Hope this helps you

6 0

3 years ago