D or A copy of the papers in my
MH₂: 2 g/mol
mNH₃: 17 g/mol
...............................
3H₂ + N₂ ---> 2NH₃
6g......................34g
6g H₂ ---- 34g NH₃
Xg -------- 13,09g
X = (6×13,09)/34
X = 2,31g H₂
In the given system, A is the central atom which is surrounded by four B atoms and forms 4 covalent bonds. Ideally, this structure could correspond to a square planar molecular geometry. However, there are two lone pairs of electrons on the central atom A which must be considered in order interpret the electron geometry.
Thus the electron domain geometry around A is octahedral
