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sergij07 [2.7K]
3 years ago
13

For each amino acid, the name, three-letter abbreviation, or one-letter abbreviation is given. Complete the missing information

name: proline three-letter abbreviation: one-letter abbreviation: Select the class (side chain) for proline. name: three-letter abbreviation: Phe name: three-letter abbreviation: Phe one-letter abbreviation: Select the class (side chain) for Phe. name: three-letter abbreviation: name: three-letter abbreviation: one-letter abbreviation: D Select the class (side chain) for D. nathe: lysine three-letter abbreviation: latihan aidantului one-letter abbreviation: Select the class (side chain) for lysine. name: three-letter abbreviation: Gin one-letter abbreviation: Select the class (side chain) for Gln.
Chemistry
1 answer:
masha68 [24]3 years ago
7 0
There is not a three letter abbreviation for Kiev. It is a two letter abbreviation which is KV. The abbreviation is typically used when booking airline travel.
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How could an alpha particle pass straight through the metal foil and strike the center of the phosphor screen on the other side
djverab [1.8K]
I think you refer to  Rutherford's Gold Foil Experiment alpha particles pass through because of the enormous amount of empty space inside the atom. 


>>>more details here<<<
to have its trajectory affected the alpha particle has to pass "near" the nucleus to interact with the positive charge of the nucleus.
the fact is that internally the gold atoms are basically empty space and the nucleus represents only a small portion of the entire volume. only few alpha particles pass near the nucleus 

picture added><><**><>< below}{<{>} 
-gio-chealafi- hope this helps you, have a nice rest of the day. ily all!!

8 0
3 years ago
Calculate the mass of vanadium(V) oxide (V2O5) that contains a million (1.0 *10^6) vanadium atoms. Be sure your answer has a uni
sweet [91]

Answer : The mass of vanadium(V) oxide will be 1.51\times 10^{-16}g

Explanation : Given,

Number of atoms of V_2O_5 = 1.0\times 10^{6}

Molar mass of V_2O_5 = 181.88 g/mole

In V_2O_5, there are 2 atoms of vanadium and 5 atoms of oxygen.

First we have to determine the moles of V_2O_5.

As, 2\times 6.022\times 10^{23} number of vanadium atom present in 1 moles of V_2O_5

So, 1.0\times 10^{6} number of vanadium atom present in \frac{1.0\times 10^{6}}{2\times 6.022\times 10^{23}}=8.3\times 10^{-19} moles of V_2O_5

Now we have to determine the mass of V_2O_5.

\text{Mass of }V_2O_5=\text{Moles of }V_2O_5\times \text{Molar mass of }V_2O_5

\text{Mass of }V_2O_5=(8.3\times 10^{-19}mole)\times (181.88g/mole)=1.51\times 10^{-16}g

Therefore, the mass of vanadium(V) oxide will be 1.51\times 10^{-16}g

4 0
4 years ago
Read 2 more answers
A new penny has a mass of 2.49 grams and occupies 0.349 cm cubed. If pure copper has a density of 8.96 g/cm cubed, is the new pe
lys-0071 [83]

Answer: The new penny is not pure copper

Explanation:

Density \rho is defined as a relation between the mass m and the volume V:

\rho=\frac{m}{V}

Now, we are told the density of pure copper is:

\rho_{copper}=8.96 g/cm^{3}

And we are given the mass and volume of the new penny, with which we can calculate its density:

\rho_{penny}=\frac{m_{penny}}{V_{penny}}=\frac{2.49 g}{0.349 cm^{3}}

\rho_{penny}=7.13 g/cm^{3} As we can see the density of this penny is not equal to the density of pure copper, hence the new penny is not pure copper.

8 0
4 years ago
A student found the mass of an object to be 5.5 g. The actual mass of the object is 5.3 g. What is the percent error in the meas
Salsk061 [2.6K]

Answer: 3.6%

5.5 - 5.3 and divide it by 5.5. Then multiply this by 100

Explanation:

This will get you 3.6%

8 0
3 years ago
Read 2 more answers
Which of the following chemical formulas show three molecules of a compound that has one
mr_godi [17]

The chemical formula : 3HgBr₂(Mercury(II) bromide)

<h3>Further explanation</h3>

Given

The chemical formulas of Mercury and Bromine

Required

The appropriate chemical formula

Solution

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

The number of molecules is determined by the coefficient in front of the compound

the number of atoms is determined by the subscript after the atom and the coefficient

Three molecules⇒ coefficient = 3

one atom of Mercury ⇒Hg

two atoms of Bromine ⇒ Br₂

The chemical formula : 3HgBr₂

6 0
3 years ago
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