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Scrat [10]
4 years ago
13

An aqueous solution contains the amino acid glycine (NH2CH2COOH). Assuming that the acid does not ionize in water, calculate the

molality of the solution if it freezes at −1.83°C. The freezing point depression constant for water is 1.86°C/m.
Chemistry
1 answer:
zmey [24]4 years ago
7 0

Answer:

Molality for this solution is 0.98 mol/kg

Explanation:

ΔT = Kf . m . i

Freezing point depression, here

ΔT =  Freezing point of pure solvent - Freezing point of solution

i = Van't Hoff factor.

This solute, the amino acid glycine does not ionize, so the i in this case is 1

Let's replace the data given

0° - (-1.83°C) = 1.86 °C/m . m . 1

1.83°C =  1.86 °C/m . m . 1

1.83°C / 1.86 m/°C = 0.98 m

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What is equal to the number of particles in 36 grams of carbon-12?
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Answer:

3 moles

Explanation:

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The number 6.022×10²³ is called Avogadro number and it is the number of atoms, ions or molecules in one mole of substance.  According to this,

1.008 g of hydrogen = 1 mole =  6.022×10²³  atoms.

18 g water = 1 mole = 6.022×10²³ molecules

we are given 36 g of C-12. So,

12 g of C-12 = 1 mole

24 g of C-12 =  2 mole

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3 years ago
What is the frequency of an electromagnetic wave that has a wavelength of
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Calculate the Ph and the POH of an aqueous solution that is 0. 040 m in HCl(aq) and 0. 075 m in HBr(aq) at 25 °C.
LenaWriter [7]

pH is the measure of the hydrogen ion concentration while pOH is of hydroxide ion concentration in the solution. The pH is 0.939 and pOH is 13.061 pOH.

pH is the concentration of the hydrogen ion released or gained by the species in the solution that depicts the acidity and basicity of the solution.

pOH is the concentration of the hydroxide ion in the solution and is dependent on the pH as an increase in pH decreases the pOH and vice versa.

Both HCl and HBr are strong acids and gets ionized 100 % in the solution. If we let 1 L of solution for the acids then the concentration of the hydrogen ion will be 0.100 M.

Since both completely dissociate we would just add the molarities of each of the H+ ions together and then calculate the PH and POH from that :

HCL(0.040M)----> H+(0.040M) +CL-(0.040M)

HBr(0.075M)----> H+(0.075M) +Br-(0.075M)

so 0.040M (H+ from HCL) + 0.075M (H+ from HBr) = 0.115M H+ in total.

pH is calculated as:

pH = -log[H+]

Substituting values in the equation:

log(0.115M)= 0.939 pH

pOH is calculated as:

14 - pH = pOH

Substituting values in the equation above:

14 - 0.939= 13.061 pOH

Therefore, pH is 0.939 and pOH is 13.061.

Learn more about pH and pOH here:

brainly.com/question/2947041

#SPJ4

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