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Scrat [10]
3 years ago
13

An aqueous solution contains the amino acid glycine (NH2CH2COOH). Assuming that the acid does not ionize in water, calculate the

molality of the solution if it freezes at −1.83°C. The freezing point depression constant for water is 1.86°C/m.
Chemistry
1 answer:
zmey [24]3 years ago
7 0

Answer:

Molality for this solution is 0.98 mol/kg

Explanation:

ΔT = Kf . m . i

Freezing point depression, here

ΔT =  Freezing point of pure solvent - Freezing point of solution

i = Van't Hoff factor.

This solute, the amino acid glycine does not ionize, so the i in this case is 1

Let's replace the data given

0° - (-1.83°C) = 1.86 °C/m . m . 1

1.83°C =  1.86 °C/m . m . 1

1.83°C / 1.86 m/°C = 0.98 m

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What mass of copper is consumed in the reaction with hydrochloric acid if 10.0 g of gas is collected?
brilliants [131]

Answer:

317 g

Explanation:

Cu + 2HCl --> CuCl2 +H2

1      :     2           1 : 1

1 mole of Cu  = 63.5 g

1 mole of  H2 = 2g

1 mole  Cu produces = 1 mole of H2

63.5 g of Cu produces = 2 g of H2

So

10 g of H2 will be produced from =  (63.5/2)*10 = 317 g of Copper

4 0
3 years ago
What is the chemical formula for the ternary compound composed of co3+ and so42- ions? coso4 co3(so4)2 co2so4 co2(so4)3 none of
Andreas93 [3]
If you are provided with Cation and an Anion with different oxidation states, then there ratio in the formula unit is adjusted as such that the oxidation number of one ion is set the coefficient of other ion and vice versa,

Example:
               Let suppose you are provided with A⁺² and B⁻¹, so multiply A by 1 and B by 2 as follow,
                                                      A(B)₂

In statement we are given with Co⁺³ and SO₄⁻², so multiply Co⁺³ by 2 and SO₄⁻² by 3, hence,

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4 0
3 years ago
How many grams of nicl2∙6h2o will be used to prepare a 0. 0350 m, 500. 0 ml of nicl2 solution?
marin [14]

The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g

<h3>What is molarity? </h3>

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of NiCl₂•6HO₂</h3>
  • Molarity = 0.035 M
  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Mole of NiCl₂•6HO₂ =?

Mole = Molarity × Volume

Mole of NiCl₂•6HO₂ = 0.035 × 0.5

Mole of NiCl₂•6HO₂ = 0.0175 mole

<h3>How to determine the mass of NiCl₂•6HO₂</h3>
  • Mole of NiCl₂•6HO₂ = 0.0175 mole
  • Molar mass of NiCl₂•6HO₂ = 238 g/mol
  • Mass of NiCl₂•6HO₂ =?

Mass = mole × molar mass

Mass of NiCl₂•6HO₂ = 0.0175 × 238

Mass of NiCl₂•6HO₂ = 4.165 g

Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution

Learn more about molarity:

brainly.com/question/15370276

3 0
2 years ago
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