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Scrat [10]
3 years ago
13

An aqueous solution contains the amino acid glycine (NH2CH2COOH). Assuming that the acid does not ionize in water, calculate the

molality of the solution if it freezes at −1.83°C. The freezing point depression constant for water is 1.86°C/m.
Chemistry
1 answer:
zmey [24]3 years ago
7 0

Answer:

Molality for this solution is 0.98 mol/kg

Explanation:

ΔT = Kf . m . i

Freezing point depression, here

ΔT =  Freezing point of pure solvent - Freezing point of solution

i = Van't Hoff factor.

This solute, the amino acid glycine does not ionize, so the i in this case is 1

Let's replace the data given

0° - (-1.83°C) = 1.86 °C/m . m . 1

1.83°C =  1.86 °C/m . m . 1

1.83°C / 1.86 m/°C = 0.98 m

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