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vova2212 [387]
4 years ago
6

Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH

is needed to fully neutralize a 10 mL aliquot of the acetic acid solution
Chemistry
1 answer:
Doss [256]4 years ago
6 0

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

    No. of moles = \frac{mass}{\text{molar mass}}

                           = \frac{12 g}{60 g/mol}

                           = 0.2 mol

Molarity of acetic acid is calculated as follows.

              Density = \frac{mass}{volume}

                 1 g/ml = \frac{100 g}{volume}

                    volume = 100 ml

Hence, molarity = \frac{\text{no. of moles}}{volume}

                           = \frac{0.2 mol}{0.1 L}

                           = 2 mol/l

As reaction equation for the given reaction is as follows.

     NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O

So,          moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

          x \times 1 M = 10 mL \times 2 M     (as 1 L = 1000 ml)

                        x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.                    

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6 0
4 years ago
How many moles of PC15 can be produced from 51.0 g of Cl2 (and excess P4)?
slava [35]

Answer:

0.287 mole of PCl5.

Explanation:

We'll begin by calculating the number of mole in 51g of Cl2. This is illustrated below:

Molar mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 = 51g

Number of mole of Cl2 =..?

Mole = Mass /Molar Mass

Number of mole of Cl2 = 51/71 = 0.718 mole

Next, we shall write the balanced equation for the reaction. This is given below:

P4 + 10Cl2 → 4PCl5

Finally, we determine the number of mole of PCl5 produced from the reaction as follow:

From the balanced equation above,

10 moles of Cl2 reacted to produce 4 moles of PCl5.

Therefore, 0.718 mole of Cl2 will react to produce = (0.718 x 4)/10 = 0.287 mole of PCl5.

Therefore, 0.287 mole of PCl5 is produced from the reaction.

8 0
3 years ago
Sodium and chlorine react to form sodium chloride. If there are 1.4 moles of sodium used, how many moles of chlorine were requir
sammy [17]

Answer:

0.7 moles of Chlorine gas is required.

Explanation:

The reaction is balanced as follows:

2Na + Cl_{2} ------>  2NaCl

According to stoichiometry,

2 mole Sodium reacts with 1 mole Chlorine gas

∴1 mole Sodium reacts with 1/2 moles of Chlorine gas

∴1.4 mole sodium reacts with 1.4/2 moles of Chlorine gas

                                                = 0.7 moles of Chlorine gas

So, 0.7 moles of Chlorine gas is required.

3 0
3 years ago
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