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Veronika [31]
3 years ago
15

At elevated temperatures, dinitrogen pentoxide decomposes to nitrogen dioxide and oxygen:_________.

Chemistry
1 answer:
fgiga [73]3 years ago
7 0

Answer:

e. 4.1 x 10^−4

Explanation:

For the reaction;

2N2O5(g) → 4NO2(g) + O2(g)

The rate of formation is given as;

(1 / 4) Δ [O2] / Δt = (1 / 2 )Δ [N2O5] / Δt

Δ [O2] / Δt = 8.1 x 10^−4 M/s

Inserting into he equation, we have;

(1/4) (8.1 x 10^−4 ) = (1/2) (Δ [N2O5] / Δt)

2.025 x 10^−4 = (1/2) (Δ [N2O5] / Δt)

Δ [N2O5] / Δt = 2 * 2.025 x 10^−4

Δ [N2O5] / Δt  =  4.1 x 10^−4

Correct option is option E.

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When a neutral atom becomes a negatively charged ion, or anion, the atom __________ electrons. a gains b loses c has no change i
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Which molecules are pure elements?
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Determine the nuclear composition (number of protons and neutrons) of the following isotopes. (a) chromium-52 protons neutrons (
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selenium - 80 :  protons = 34, neutrons = 46

molybdenum-98:  protons = 42, neutrons = 56

xenon-132:  protons = 54, neutrons = 78

ytterbium-174 :  protons = 70, neutrons = 104

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Thus, number of protons = atomic number

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

a) chromium-52 :

Atomic number of Chromium is 24 hence number of protons  = 24

52= 24+ Number of neutrons

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b) selenium - 80 :

Atomic number of selenium is 34 hence number of protons  = 34

80 =  34 +  Number of neutrons

Number of neutrons = 46

c) molybdenum - 98 :

Atomic number of molybdenum is 42 is  hence number of protons  = 42

98 =  42 +  Number of neutrons

Number of neutrons = 56

d) xenon-132:

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132 =  54 +  Number of neutrons

Number of neutrons = 78

e) ytterbium-174:

Atomic number of ytterbium is 70 and  hence number of protons  = 70

174 = 70 +  Number of neutrons

Number of neutrons = 104

6 0
3 years ago
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