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Svetradugi [14.3K]

4 years ago

14

For example: The solid is not completely submerged in the water. Will this technique error increase, decrease, or have no effect

on the reported density of the solid?

1 answer:

Darya [45]4 years ago

8 0

Density is the amount of matter in an object so having it any way submerged in water will not affect the solid's density

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What particles are used for artificial transmutations?

Doss [256]

Answer:

C

Explanation:

6 0

4 years ago

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It is known that 32g of oxygen takes up 24 litres of space at 25oC. Calculate the volume of oxygen that is needed to react compl

Gwar [14]

6 L of oxygen (O₂)

Explanation:

We have the following chemical reaction:

2 Mg + O₂ → 2 MgO

Now we calculate the number of moles of magnesium:

number of moles = mass / molar weight

number of moles of Mg = 12 / 24 = 0.5 moles

Taking in account the chemical reaction we devise the following reasoning:

if 2 moles of Mg react with 1 mole of O₂

then 0.5 moles of Mg react with X moles of O₂

X = (0.5 × 1) / 2 = 0.25 mole of O₂

mass = number of moles × molar weight

mass of O₂ = 0.25 × 32 = 8 g

Knowing the information given by the problem that 32 g of O₂ takes up 24 liters of space, we devise the following reasoning:

if 32 g of O₂ takes up 24 liters of space

then 8 g of O₂ takes up Y liters of space

Y = (8 × 24) / 32 = 6 L of O₂

Learn more about:

balancing chemical reactions

brainly.com/question/14187466

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4 0

3 years ago

1.If 6 moles of KNO3 should be produced in a reaction, but only 4.78 mol KNO3 are produced, what is the % yield?

irakobra [83]

Answer:

79.7%

Explanation:

Percent yield of reaction is defined as the ratio between theoretical yield of a reaction and actual yield obtained.

In the problem, theoretical yield are 6 moles of KNO₃ and actual yield are 4.78 moles. Thus, percent yield is:

4.78 mol / 6 mol × 100 =<em> 79.7%</em>

3 0

3 years ago

The half life of tritium is 12.3 years. How much sample will remain if you start with 425g of tritium that is found after 4 half

natta225 [31]

Answer:

26.56g

Explanation:

The half life of an isotope decay is the time transcurred when the initial amount of the isotope decays to the half of its amount.

For the problem, when 1 half life transcur, the sample has a mass of:

425g / 2 = 212.5g

When 2 half lives transcur:

212.5g / 2 = 106.25g

3 half lives:

106.25/2 = 53.13g

And the amount that is found after 4 half lives is:

53.13/2 =

<h3>26.56g</h3>

3 0

3 years ago

Which profile best describes the reaction C(s) + 2H2(g) → CH4(g),<br> AH = -74.9 kJ?

katrin [286]

Answer:

Option B. A

Explanation:

From the question given above, the following data were obtained:

C(s) + 2H₂ (g) —> CH₄ (g). ΔH = –74.9 kJ

From the reaction above, we can see that the enthalpy change (ΔH) is negative (i.e –74.9 KJ) which implies that the heat content of the reactants is greater than the heat content of the products. Thus, the reaction is exothermic reaction.

For an exothermic reaction, the energy profile diagram is drawn in such a way that the heat content of reactants is higher than the heat content of products because the enthalpy change

(ΔH) is always negative.

Thus, diagram A (i.e option B) gives the correct answer to the question.

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3 years ago

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