Answer:
Explanation:
Na + Cl = NaCl
23 g 35.5 g
23 g sodium reacts with 35.5 g of chlorine
29 g of sodium reacts with 35.5 x 29 / 23 g of chlorine
= 44.76 g
So 44.76 g of chlorine reacts and 49 - 44.76 = 4.24 g of chlorine is left over .
All the sodium is used up in the reaction .
KOH is the limiting reagent
The molar ratio is 1:2
So if you have 6 moles of MgCl2 you need 12 moles of KOH
When preparing diluted solutions from concentrated solutions , we can use the following equation;
c1v1 =c2v2
Where c1 and v1 are the concentration and volume of the concentrated solution
c2 is the concentration of the diluted solution to be prepared
v2 is the volume of the diluted solution
Substituting the values;
12.0 M x v1 = 0.339 M x 100 mL
v1 = 2.825 mL needs to be taken from the stock solution
