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PilotLPTM [1.2K]
2 years ago
6

A 1.33 g sample of water is injected into a closed evacuated 4.81 liter flask at 65°C. What percent (by mass) of the water will

be vapor when equilibrium is reached? (the vapor pressure of water at 65°C is 187.5 mmHg)
Chemistry
1 answer:
svetoff [14.1K]2 years ago
4 0

Answer:

52.5

Explanation:

how you get that is you divide be 3 to get the answer

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How many bromine atoms are present in 37.5 g of CH2Br2?
ella [17]
<span>37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2

4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
5 0
2 years ago
Percent concentration is one of the most common and basic concentration measurement used by general public. true or false?
Aleksandr [31]

Answer:

  • <u>TRUE:</u> <em>Percent concentration is one of the most common and basic concentration measurement used by general public</em>

Explanation:

In chemistry there are many <em>concentration measurements</em> used to describe the mixtures. Some of them are, percent, molarity, molality, and molar fraction, among others.

Percent concentration is a popular one because it is commonly understood and used by the non specialist people, i.e. general public.

The percent concentration of a component is defined as: (amount of component in the mixture / amount of mixture) × 100.

The amounts may be measured in mass units (e.g grams) or volume units (e.g. mililiters).

For solutions, mass percent concentration is:

  • % = (mass of solute / mass of solution) × 100.

And voluem percen contration is:

  • % = (volume of solute / volume of solution) × 100

Since percentage is used in many profesional and personal activities, most persons use it.

For example, rubbing alcohol, that everyone buys in pharmacies, is 70%; vinager, used in the food, is acetic acid at 5% - 8%.

5 0
3 years ago
Which chemical formal shows an ionic compound? A. CO2 B.N 2 O C.NaCI D.C6 H12 O6
KonstantinChe [14]

Answer:

B

N2O

Explanation:

maybe

d can also be lol

4 0
2 years ago
What mass of water is produced by the combustion 1.2 x 10^26 molecules of butane ?
podryga [215]

Answer:

17.934 kg of water

Explanation:

If balanced equation is not given; this format can come in handy.

For any alkane of the type : CₙH₂ₙ₊₂ , it's combustion reaction will follow:

2CₙH₂ₙ₊₂ + (3n+1) O₂  →  (2n)CO₂ + 2(n+1) H₂O

For butane:

2C₄H₁₀(g) + 13O₂(g) →  8CO₂(g) + 10H₂O(l)

2 moles of butane gives 10 moles of water.

1 mol of any substance has Avogadro number(N) of molecules in it( 6.022 x 10²³)

Mass of 1 mole of any substance is equal to it's molar mass

So, if 2 x N molecules of butane gives 10 x 18 g of water.

Then  1.2 x 10²⁶ molecules will give:

\frac{1.2 \times 10^{26} \times 180}{2 \times 6.022 \times  10^{23}}

= 17.934 x 10³ g of water

= 17.934 kg of water

5 0
3 years ago
when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to blank k
Makovka662 [10]
Guy-Lussac's Law states that the volume and the temperature are directly proportional given that the pressure remains constant.

For this problem, we will assume constant pressure. Based on the law:
(Volume/Temperatur)1 = (Volume/Temperature)2
(3.75/100) = (6.52/T)
T = 166.667 kelvin
4 0
3 years ago
Read 2 more answers
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