The answer is 1.
1² = 1
20×1² = 20×1
Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph
To Find : Maximum profit , breakeven point , profit interval
Solution:
The maximum profit the florist will earn from selling celebration bouquets is $ 675
peak of y from Graph
The florist will break-even after Selling 20 one-dollar decreases.
at breakeven
Break even is the point where the profit p(x) becomes 0
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).
after 20 , P(x) is - ve
the answer is D.
there is not enough information
What you’re doing is breaking it down into its parts and writing it into an equation that way long hand.
3 + .4 + .00 + .005
