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alexandr402 [8]
3 years ago
8

Given that the density of Hg(l) at 0°C is about 14 g mL-­1, which of the following is closest to the volume of one mole of Hg(l)

at this temperature?
Chemistry
1 answer:
Mila [183]3 years ago
8 0

Answer: 14mL

Explanation:

From the question, we've been told that the that the density of Hg(l) at 0°C is about 14 g mL-­1.

14g = 1mL

We should note that atomic weight of mercury = 200.59.

Therefore, 1 mol Hg = 200.59 g

Therefore, the answer that is closest to the volume of one mole of Hg(l) at this temperature will be:

= 200.59/14

= 14.3 mL

= 14mL approximately

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2 years ago
A 0.5895-g sample of impure magnesium hydroxide is dissolved in 100.0 mL of 0.2050 M HCl solution. The excess acid then needs 19
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Answer:

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Explanation:

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number of moles = molar concentration × solution volume

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reaction between NaOH and HCl:

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If 2.02 mmoles of NaOH were used for neutralization of HCl left from the reaction, which are 2.02 mmoles of HCl, it means that the HCl reacted with Mg(OH)₂:

20.5 - 2.02 = 18.48 mmoles of HCl

2 HCl + Mg(OH)₂ = MgCl₂ + 2 H₂O

From the chemical reaction we devise the following reasoning:

if       2 mmoles of HCl react with 1 mmole of Mg(OH)₂

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X = (18.48 × 1) / 2 = 9.24 mmoles of Mg(OH)₂

now the mass of Mg(OH)₂:

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In density when mass goes up does volume go down?
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