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alexandr402 [8]
3 years ago
8

Given that the density of Hg(l) at 0°C is about 14 g mL-­1, which of the following is closest to the volume of one mole of Hg(l)

at this temperature?
Chemistry
1 answer:
Mila [183]3 years ago
8 0

Answer: 14mL

Explanation:

From the question, we've been told that the that the density of Hg(l) at 0°C is about 14 g mL-­1.

14g = 1mL

We should note that atomic weight of mercury = 200.59.

Therefore, 1 mol Hg = 200.59 g

Therefore, the answer that is closest to the volume of one mole of Hg(l) at this temperature will be:

= 200.59/14

= 14.3 mL

= 14mL approximately

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garri49 [273]

Answer:

digital camera

Explanation:

4 0
3 years ago
Enter your answer in the provided box.
Lina20 [59]

Answer:

5.06atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1.34 atm

P2 = ?

V1 = 5.48 L

V2 = 1.32 L

T1 = 61 °C = 61 + 273 = 334K

T2 = 31 °C = 31 + 273 = 304K

Using P1V1/T1 = P2V2/T2

1.34 × 5.48/334 = P2 × 1.32/304

7.34/334 = 1.32P2/304

Cross multiply

334 × 1.32P2 = 304 × 7.34

440.88P2 = 2231.36

P2 = 2231.36/440.88

P2 = 5.06

The final pressure is 5.06atm

6 0
3 years ago
Help pls! Answer all of it. Idk if what I wrote is correct.
trasher [3.6K]
The reaction is actually endothermic because delta H is positive, indicating that it absorbing heat. 
8 0
3 years ago
Cevabı atar mısınız lütfen​
yawa3891 [41]
I’m sorry I don’t understand if you can may you say it in English?
4 0
2 years ago
How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr
pickupchik [31]

Answer: There are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = 87.5^{o}C = (87.5 + 273) K = 360.5 K

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

0.244 mol \times 6.022 \times 10^{23}\\= 1.469 \times 10^{23}

Thus, we can conclude that there are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

5 0
3 years ago
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