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kiruha [24]
3 years ago
10

Which of the following groups is not reactive? Circle all that apply.

Chemistry
1 answer:
Verizon [17]3 years ago
5 0
D. Noble Gases

Hope this helps!
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A solution of acetic acid has a pH of 3.45. What is the concentration of acetic acid in this solution? Ka for CH3COOH is 1.8×10-
Serjik [45]

Answer:

0.007 M

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

pH=-log(\sqrt{k_a\times C})

Where, C is the concentration = ?

Given, pH = 3.45

So, for CH_3COOH, K_a=1.8\times 10^{-5}

3.45=-log(\sqrt{1.8\times 10^{-5}\times C})

\log _{10}\left(\sqrt{1.8\cdot \:10^{-5}C}\right)=-3.45

C = 0.007 M

5 0
3 years ago
Write the name for the compound Al₂S₃
Svetlanka [38]

Answer:

Uh Joe stinky?

Explanation:

7 0
3 years ago
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14. 60. g of NaOH is dissolved in enough distilled water to make 300 mL of a stock solution. What volumes of this solution and d
zepelin [54]

The question is incomplete, the complete question is attached below.

Answer : The volumes of stock solution and distilled water will be, 20 mL and 80 mL respectively.

Explanation : Given,

Mass of NaOH = 60 g

Volume of stock solution = 300 mL

Molar mass of NaOH = 40 g/mol

First we have to calculate the molarity of stock solution.

\text{Molarity}=\frac{\text{Mass of }NaOH\times 1000}{\text{Molar mass of }NaOH\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{60g\times 1000}{40g/mole\times 300mL}=5mole/L=5M

Now we have to determine the volume of stock solution and distilled water mixed.

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of stock solution.

M_2\text{ and }V_2 are the molarity and volume of diluted solution.

From data (A) :

M_1=5M\\V_1=20mL\\M_2=1M\\V_2=?

Putting values in above equation, we get:

5M\times 20mL=1M\times V_2\\\\V_2=100mL

Volume of stock solution = 20 mL

Volume of distilled water = 100 mL - 20 mL = 80 mL

From data (B) :

M_1=5M\\V_1=20mL\\M_2=1M\\V_2=?

Putting values in above equation, we get:

5M\times 20mL=1M\times V_2\\\\V_2=100mL

Volume of stock solution = 20 mL

Volume of distilled water = 100 mL - 20 mL = 80 mL

From data (C) :

M_1=5M\\V_1=60mL\\M_2=1M\\V_2=?

Putting values in above equation, we get:

5M\times 60mL=1M\times V_2\\\\V_2=300mL

Volume of stock solution = 60 mL

Volume of distilled water = 300 mL - 60 mL = 240 mL

From data (D) :

M_1=5M\\V_1=20mL\\M_2=1M\\V_2=?

Putting values in above equation, we get:

5M\times 60mL=1M\times V_2\\\\V_2=300mL

Volume of stock solution = 60 mL

Volume of distilled water = 300 mL - 60 mL = 240 mL

From this we conclude that, when 20 mL stock solution and 80 mL distilled water mixed then it will result in a solution that is approximately 1 M NaOH.

Hence, the volumes of stock solution and distilled water will be, 20 mL and 80 mL respectively.

5 0
3 years ago
Which of the following has the greatest mass, in grams? 1 atom of lead (Pb) 0.5 mol silver (Ag) atoms 0.3 mol gold (Au) atoms 25
Strike441 [17]

Answer : Option C) 0.3 mol of Gold.

Explanation : Amongst the options given in the question, 0.3 mol of Au is the greatest in mass in grams.

As 0.3 mol X atomic weight of Au (196.966) = 59.088 grams;

Silver has 0.5 mol X atomic weight of Ag (107.86) = 53.93 grams;

The other options are not relevant as they deal in the atomic range which has mass value very less as compared to the moles of elements.

Therefore, it is clear that Au has the greatest mass amongst the given choices.

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4 years ago
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What kind of bond would a metal and a nonmetal typically make?
lana66690 [7]
A) ionic bond.......
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