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tangare [24]
3 years ago
13

What is the area of a triangle with a base length of 2 1/2 inches and a height of 2 inches

Mathematics
1 answer:
Sedaia [141]3 years ago
6 0
Hello I am happy to help you with this problem. So the formula to solve for a triangle is A = bxh divided by 2.
So it’s area equals base times height divided by 2. So the base is 2 1/2 which becomes 5/2 ( five over 2) times 2 which equals 5. It’s because you cancel. So 5 divided by 2 equals 5/2 which also equals 2 1/2.



I hope that helps you. If you have any questions please feel free to ask me.
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Find the range of the function f(x)=x2+5 given the domain (-2,-1,0,1,2)?
iren2701 [21]

Answer:

(5, 6, 9)

Step-by-step explanation:

The domain is basically the set of all x values while the range is the set of all y values, in this case, it's the values of f(x). To find the range, we can plug the x values into the equation:

f(-2) = 9

f(-1) = 6

f(0) = 5

f(1) = 6

f(2) = 9

Since we can't have repeats in the range, it would be: (5, 6, 9)

6 0
2 years ago
It takes 3 hours 15 minutes to fly from city A
Alex777 [14]

Answer:

19.5

4555.555555555555 hz

Step-by-step explanation:

5 0
3 years ago
What is the angle relationship shown below?
Harman [31]

Answer:

The relationship between the angles is alternate exterior angles.

Step-by-step explanation:

Exterior means outside.

Alternate means every other or in this case across form each other.

These angles represent alternate exterior angles because they are on the outside of the transversal and they are alternating each other.

8 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
sladkih [1.3K]

Answer:

10.17 seconds

Step-by-step explanation:

substitute y=0 into the equation

0=-16x²+153x+98

then use the quadratic formula

a = -16

b= 153

c = 98

Substituting values into the Quadratic equation, you get (Round the values to the nearest hundreth):

x₁= 10.17

x₂= -0.60

5 0
2 years ago
A jet’s speed in still air is 240 mph. One day it flew 700 miles with a tailwind (the wind pushing it along) and then returned t
Bess [88]

Speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

As given in the question,

Given data:

Jet speed in still air = 240mph

Let x be the speed of the wind.

Speed with tail wind = 240 +x

Distance covered with tail wind = 700miles

Time taken by jet with tail wind

= Distance/ speed

= 700 / (240 +x)  __(1)

Speed against the wind = 240 - x

Distance covered against the wind = 700miles

Time taken by jet against the wind

= Distance/ speed

= 700 / (240 - x)  __(2)

Total time taken is 6 hours

[700 / (240 +x)] + [700 / (240 - x)] = 6

⇒ 700( 240 -x + 240 + x) = 6 (240 +x)(240 - x)

⇒ 700 ( 480) = 6 ( 240² -x²)

⇒ 700 (80) = 57600 -x²

⇒ x² = 57600 - 56000

⇒ x² = 1600

⇒ x = √1600

⇒ x= 40 mph

Therefore, speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

Learn more about speed here

brainly.com/question/28224010

#SPJ1

6 0
1 year ago
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