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shtirl [24]
3 years ago
14

A jar contains 8 red marbles numbered 1 to 8 and 4 blue marbles numbered 1 to 4. A marble is drawn at random from the jar. Find

the probability that the marble is blue or odd-numbered.
Mathematics
1 answer:
Daniel [21]3 years ago
4 0

Answer:

66.6%

Step-by-step explanation:

The probability that it is blue or odd, would be the quotient between the marbles of these characteristics and the total number of marbles.

Now, we know that there are four blue marbles altogether. The odd ones, in the case of the red ones since there are eight, are the marbles 1,3,5,7 and in the blue ones the odd ones are not counted because they are already included as blue; therefore there are a total of four odd marbles. In total, between odd and blue there are eight marbles.

Which means that the probability is as follows, knowing that there are a total of 12 marbles:

8/12 = 0.666, that is, there is 66.6% chance that the marble that is drawn is blue or an odd number.

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Luis put out
solniwko [45]

Answer:

<u><em>2 1/4 pies</em></u>

Step-by-step explanation:

Find out how much pie was leftover from each pie:

Apple pie: 3/4, 4 - 3 = 1, 1/4

Blackberry: 1/2, 2 - 1 = 1, 1/2

Blueberry: 1/8, 8 - 1 = 7, 7/8

Cherry: 5/8, 8 - 5 = 3, 3/8

Peach: 3/4, 4 - 3 = 1, 1/4

There are 1/4, 1/2, 7/8, 3/8, and 1/4 pies left. The LCD if these numbers is 8, since 2*4 = 8, 4*2 = 8, and 8*1 = 8

1/4 = 2/8

1/2 = 4/8

7/8 = 7/8

3/8 = 3/8

1/4 = 2/8

2 + 4 + 7 + 3 + 2 = 18, so 18/8 pies, or 2 2/8, or 2 1/4

5 0
3 years ago
Read 2 more answers
Add-ons Helplast edit was seconds ago
aleksandr82 [10.1K]
Eeeeeeeeeeeeeeeeee eeeeeeeeeeeeeeeee
6 0
3 years ago
You want to put a fence around your field. The cost of fencing is $60 per meter. The
Darina [25.2K]
Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
-> W = 50/2
-> Width of rectangular field = 25m
Cost of one field length(l) = L x C
-> l = 50 x 60
-> l = $3000
Two of the lengths of the field = 2 x l
-> 2 x $3000
-> $6000

Cost of one field width(w) = W x C
-> w = 25 x 60
-> w = $1500
Two of the widths of the field = 2 x w
-> 2 x $1500
-> $3000

Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000


3 0
3 years ago
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
Image point B (4,-8) was transformed using the translation (x-2,y+3) what were the coordinates of B?
PilotLPTM [1.2K]
The coordinates of the image point are given to be B(4, -8). We are to find the coordinates of pre-image that is the coordinates before the translation.

The translation made was (x-2, y+3) 

This means, the x coordinate was moved 2 units to left and y coordinate was moved 3 units above. 

So, the coordinates of original point will be, 2 units to right of B and 3 units down of B.

So the coordinates will be (6, -11)
 
5 0
3 years ago
Read 2 more answers
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