Divide both sides by 49/36 to get y by itself:
Simplify this fraction:
Now you have your answer:
Answer:
y = -4
Step-by-step explanation:
-2x + 5y = 8
Let x=-14
-2(-14) +5y = 8
28 +5y = 8
Subtract 28 from each side
28-28 +5y = 8-28
5y = -20
Divide by 5
5y/5 = -20/5
y = -4
Answer: No. Kyle will arrive late
Step-by-step explanation:
The only speed limit is 50 miles per hour.
Kyle must cover 130 miles.
His travel time = 130/50 = 2.6
2 hours + (0.6 of 60 minutes )
2 hours + (36 minutes)
i.e kyle needs 2hours 36 minutes to cover 130 miles
And since the baseball starts in 2 hours, kyle will be late. Thus, the answer is No
Consider the charge for parking one car for t hours.
If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.
If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.
75% is 75/100 or 0.75.
For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be
0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:
3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].
Thus, the function which total parking charge of parking 3 cars for t hours is:
</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1))
Answer: C</span>
<u>Answer:</u>
<u>Step-by-step explanation:</u>
Given:
Mint condition coins = 
Total number of coins = 
Ratio
The questions asks for the ratio between mint condition coins to the total number of coins, so:
Mint condition coins : number of coins = 
(simplified form)
Hope this helps :)
