Answer:
how large a magnetic field would you experience = 8.16 x 10∧-4T
Explanation:
I = 20KA = 20,000A
r = 4.9 m
how large a magnetic field would you experience = u.I/2πr
how large a magnetic field would you experience = (4π x10∧-7) × 20000/2π × 4.9
how large a magnetic field would you experience = 8.16 x 10∧-4T
The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N
<h3>Data obtained from the question </h3>
- Initial velocity (u) = 8.5 m/s
- Final velocity (v) = 7.5 m/s
- Time (t) = 5 ms = 0.25 s
- Mass (m) = 2.5 Kg
- Force (F) = ?
<h3>How to determine the force</h3>
The force exerted on the ball can be obtained as follow:
F = m(v + u) / t
F = [2.5(7.5 + 8.5)]/ 0.25
F = 40 / 0.25
F = 160 N
Thus, the force exerted on the ball is 160 N
Learn more about momentum:
brainly.com/question/250648
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Answer:
The new resistance comes out to be = 4 times of original resistance .
Answer:
0.5 Ohms
Explanation:
We note that the node Q is also between the resistors of 1ohm and 2ohms.
We note that the node P is also between the resistors of 2ohms and 3ohms.
Thus, all these resistors are in parallel, beween nodes P and Q
1/Re=1/R1+1/R2+1/R3
1/Re=1/1+1/2+1/3=(6+3+2)/6=11/6 [ohm^(-1)]
Re=6/11=0.54ohms
Rounding to the tenth: Re=0.5 ohms
