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3 years ago

The population of a town went from 18,000 to 17,460

Mathematics

1 answer:

MaRussiya [10]3 years ago

3 0

Which would mean that 540 people died or left the town.

I hope that this helps! :D

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What is the name of the point where the three altitudes of a triangle intersect?

san4es73 [151]

Answer:

D point of conncurrency of the altitudes

the second one i am not sure of but that is the first part to your answer

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Pls help me with this! (Links=report)

xxMikexx [17]

Answer:

XZ=12 in

Step-by-step explanation:

area of a rhombus is A=pq/2

where p=WY=15.5 and A=93 and q=XZ

93=15.5(XZ)/2

93(2)=15.5(XZ)

186/15.5=XZ

XZ=12 in

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3 years ago

Which statement does not use probability correctly to describe an event?

DerKrebs [107]

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3 years ago

Patricia can buy individual songs for $1.00 to download. Also, an entire album costs $10.00 to download. She can spend no more t

Burka [1]

The system of linear inequalities x + 10y ≤ 80, x ≥ 30 and y ≤ 4 is represented in a graph below

<h3>Graph of Linear Inequality</h3>

The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality.

To solve this problem, we would require the use of graph which can easily be done with a graphing calculator.

x + 10y ≤ 80

x ≥ 30

y ≤ 4

The graph of the inequalities is attached below

Learn more on graph of linear inequality here;

brainly.com/question/19443475

#SPJ1

4 0

1 year ago

Suppose that you are given a bag containing n unbiased coins. You are told that n-1 of these coins are normal, with heads on one

gladu [14]

Answer:

The (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

Step-by-step explanation:

Given

Total unbiased coin = n

Normal coins =n - 1

Fake = 1

The (conditional) probability that the coin you chose is the fake coin is represented by

P(Fake | Head)

And it's calculated as follows;

P(Fake | Head) = P(Fake, Head) ÷ P(Head) ----- (1)

Where P(Fake, Head) = P(Fake) * P(Head | Fake)

P(Fake) = 1/n --- because only one is fake

P(Head | Fake) = n/n because all coins (including the fake) have head

So, P(Fake, Head) = P(Fake) * P(Head | Fake) becomes

P(Fake, Head) = 1/n * n/n

P(Fake, Head) = 1/n

P(Head) is calculated by

P(Fake) * P(Head | Fake) + P(Normal) * P(Head | Normal)

P(Fake) * P(Head | Fake) = P(Fake, Head) = 1/n (as calculated above)

P(Normal) * P(Head | Normal) = ½ * (n - 1)/n ----- considering that the coin also has a tail with equal probability as that of the head.

Going back to (1)

P(Fake | Head) = P(Fake, Head) ÷ P(Head) becomes

P(Fake | Head) = (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ (1/n + (n - 1)/2n)

= (1/n) ÷ (2 + n - 1)/(2n)

= (1/n) ÷ (1 + n)/(2n)

= (1/n) * (2n)/(1 + n)

= 2/(1 + n)

Hence, the (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

5 0

3 years ago