Answer:
2AlCl3 + 3H2SO4 → Al2(SO4)3 + 6HCl
Explanation:
Answer:
The substance that remained on the filter paper is Al(OH).
Explanation:
- Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
- So in our experiment the product formed is aluminum hydroxide Al(OH) and sodium chloride (NaCl).
- Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
- Hence aluminum hydroxide being only solid product remains on the filter paper.
Answer:
Zinc
Zinc blende
(ZnS)
-----------------
Lead
Galena
(PbS)
-----------------
Mercury
Cinnabar
(HgS)
----------------
Copper
Copper glance
(Cu2S)
-------------------
Explanation:
Had to learn this for a test
Also, I plead the 5th