Answer:
<em>The number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in. ... the number of electrons in all shells of an element is represented in the periodic table as the element's atomic number.</em>
Explanation:
<em>thatdummyemily </em>
<em>hope this helps srry if it doesn't tho, but if it does help can u plz mark me brainlist</em>
Answer:
<em>Three (3) of the molecules are polar: </em>
<em> </em>
<em> </em>
<em>.</em>
Explanation:
Polar substances have their elements held together by a covalent bond that contain partially positive and negative charges, which results in a difference in the charges' electronegativity difference (usually ranging between 0.4 and 0.7).
- PCl5 is <u>non-polar</u> with a symmetric geometry
- CoS is <u>polar</u>
- XeO3 is <u>polar</u>, with a trigonal pyramidal molecular geometric
- SeBr2 is <u>polar</u> as the difference their electronegativity is about ).5
Answer:
The valid quantum numbers are l=0, l=-2 and l= 2.
Explanation:
Given that,
n = 3 electron shell
Suppose, the valid quantum numbers are
l = 3
m = 3
l = 0
m = –2
l = –1
m = 2
We know that,
The value of n = 3
Principle quantum number :
Then the principal quantum number is 3. Which is shows the M shell.
So, n = 3
Azimuthal quantum number :
The azimuthal quantum number is l.
![l=0,1,2](https://tex.z-dn.net/?f=l%3D0%2C1%2C2)
Magnetic quantum number :
The magnetic quantum number is
![m=-2,-1,0,1,2](https://tex.z-dn.net/?f=m%3D-2%2C-1%2C0%2C1%2C2)
Hence, The valid quantum numbers are l=0, l=-2 and l= 2.
Answer:
The acceleration is: ![4m/s^2](https://tex.z-dn.net/?f=4m%2Fs%5E2)
Explanation:
Given
--- The initial velocity
--- time
-- The final velocity
Required
Determine the acceleration
To do this, we make use of the first equation of motion
![v = u - at](https://tex.z-dn.net/?f=v%20%3D%20u%20-%20at)
We used negative because the car was coming to stop.
This gives:
![0 = 30 - 7.5 * a](https://tex.z-dn.net/?f=0%20%3D%2030%20-%207.5%20%2A%20a)
![0 = 30 - 7.5a](https://tex.z-dn.net/?f=0%20%3D%2030%20-%207.5a)
Collect like terms
![7.5a = 30](https://tex.z-dn.net/?f=7.5a%20%3D%2030)
Solve for a
![a = \frac{30}{7.5}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B30%7D%7B7.5%7D)
![a = 4m/s^2](https://tex.z-dn.net/?f=a%20%3D%204m%2Fs%5E2)