Why isnt my grandma talking to me

Chemistry

1 answer:

Rufina [12.5K]2 years ago

4 0

Answer:

She saw you at the elderly N*de swimming event.

Explanation: You tell me...

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What is the percent yield if 3.47 g of copper is produced when 1.87 g of aluminium is reacted with excess of copper (II) sulfato

Serhud [2]

Answer:

copper is limiting

Explanation:

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1 year ago

What is the change in density if a sample goes from 3.21 g/L to 5.43 g/mL?

Step2247 [10]

Answer:

$\Delta \rho =2.22 g/mL$

Explanation:

Hello,

In this case, since a change in science is widely known to be considered as a subtraction between the the final and initial values of two measured variables and is represented via Δ, here the final density is 5.43 g/mL and the initial one was 3.21 g/mL, therefore, the change in density is:

$\Delta \rho=\rho _f-\rho _i\\ \\\Delta \rho=5.43g/mL-3.21g/mL\\\\\Delta \rho =2.22 g/mL$

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2 years ago

What can you conclude about these two reactions based on the chemical equations? Reaction A: 6CO2(g) + 6H2O(l) + sunlight ? C6H1

OlgaM077 [116]

Given reactions:

(A) 6CO2(g) + 6H2O(l) + sunlight → C6H12O6(aq) + 6O2(g)

(B) 2H2(g) + O2(g) → 2H2O(g) + energy

Exothermic reactions are those which proceed with the release of heat/energy. In contrast, endothermic reactions proceed with the absorption of energy in the form of heat or light.

Since reaction A required sunlight, it is endothermic. Reaction B releases energy, hence exothermic

Ans: (B)

A is endothermic

B is exothermic

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2 years ago

The outside boundary of an animal cell

Wewaii [24]

Plasma membrane is the answer

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3 years ago

Problem Page Question It takes to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbo

Marizza181 [45]

This is a incomplete question. The complete question is:

It takes 348 kJ/mol to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon. Round your answer to correct number of significant digits

Answer: 344 nm

Explanation:

$E=\frac{Nhc}{\lambda}$