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lorasvet [3.4K]
2 years ago
11

Christine sets up an experiment to find out if the amount of fertilizer added to soil affect how many strawberries grow on a str

awberry plant. What would be the dependent variable in Christine's experiment
A. the amount of fertilizer added to the soil

B. the number of strawberries growing on each plant

C. the amount of water used to water

D. the strawberry plants the size of the strawberries growing on the plants ​
Chemistry
1 answer:
Vadim26 [7]2 years ago
6 0

Answer:

Christine ate the fertilizer

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A voltaic cell made of a Cr electrode in a solution of 1.0 M in Cr3+ and a gold electrode in a solution that is 1.0 M in Au3+.
Vikki [24]

Answer: a) Anode: Cr\rightarrow Cr^{3+}+3e^-

Cathode: Au{3+}+3e^-\rightarrow Au

b) Anode : Cr

Cathode : Au

c) Au^{3+}+Cr\rightarrow Au+Cr^{3+}

d) E_{cell}=2.14V

Explanation: - 

a) The element Cr with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

At cathode: Au{3+}+3e^-\rightarrow Au

At anode: Cr\rightarrow Cr^{3+}+3e^-

b) At cathode which is a positive terminal, reduction occurs which is gain of electrons.

At anode which is a negative terminal, oxidation occurs which is loss of electrons.

Gold acts as cathode ad Chromium acts as anode.

c) Overall balanced equation:

At cathode: Au{3+}+3e^-\rightarrow Au     (1)

At anode: Cr\rightarrow Cr^{3+}+3e^-        (2)

Adding (1) and (2)

Au^{3+}+Cr\rightarrow Au+Cr^{3+}

d)E^0_(Cr^{3+}/Cr)= -0.74 V

E^0_(Au^{3+}/Au)= 1.40 V  

E^0{cell}=E^0{cathode}-E^0{anode}=1.40-(-0.74)=2.14V

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Au^{3+}]}{[Cr^{3+}]^}

where,

n = number of electrons in oxidation-reduction reaction = 3

E^o_{cell} = standard electrode potential = 2.14 V

E_{cell}=2.14-\frac{0.0592}{3}\log \frac{[1.0}{[1.0]}

E_{cell}=2.14

Thus the standard potential for an electrochemical cell with the cell reaction is 2.14 V.

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3 years ago
What causes London dispersion forces?
DENIUS [597]
The London Dispersion force is a temporary attratctive force that results when the electrons in 2 adjacent atoms occupy position that makes the atom form temporary dipoles.
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