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lesantik [10]
3 years ago
10

Round 2.58 to 1 sigfig Your answer

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

3

Explanation:

2.58=>3(1 significant digit)

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How many moles are in 281 g of Ca(OH)2?
Natasha_Volkova [10]

Answer:

3.79 moles

Explanation:

To convert moles to gams of a substance we need to find the molar mass of the substance. For Ca(OH)₂ th molar mass is:

1Ca = 40.08g/mol

2O = 2*16g/mol = 32g/mol

2H = 2*1.01g/mol = 2.02g/mol

The molar mass is:

40.08g/mol + 32g/mol + 2.02g/mol = <em>74.1g/mol</em>

<em />

And moles are:

281g * (1mol / 74.1g) =

<h3>3.79 moles</h3>
5 0
3 years ago
What volume of 1.10 M SrCl2 is needed to prepare 525 mL of 5.00 mM SrCl2?
grigory [225]

Answer:- 2.39 mL are required.

Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 and M_2 are molarities of concentrated and diluted solutions and V_1 and V_2 are their respective volumes.

M_1 = 1.10M

M_2 = 5.00mM = 0.005M    (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)

V_1 = ?

V_2 = 525 mL

Let's plug in the given values in the formula:

1.10M(V_1)=0.005M(525mL)

V_1=(\frac{0.005M*525mL}{1.10M})

V_1=2.39mL

So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.

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3 years ago
1) Which of the following is NOT a step in the scientific method *
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Answer:

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Condensation is the change in state of matter from gas to liquid.
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