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lisov135 [29]
4 years ago
6

NA + 1.82 x nA = 2.0 x 10^-2. How do you solve for nA?

Chemistry
1 answer:
shtirl [24]4 years ago
4 0
I have provided the steps and solution.

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Why does one beach have purple sand and another beach have pink sand?
Gnesinka [82]
Ok so I’m going to break it up so it’s a bit easier to read through:

The colours are from the different rocks and minerals that make up the sand.

The little fragments of rock come from for example surrounding mountains.

It could also because sand is simply the product from erosion of the rocks rubbing each other under the action of the waves.

So if the bottom of the ocean is made of black lava for example in Hawaii, there’s a good chance of the sand being black.

In California, the sand usually looks white because it has minerals like quartz and pieces of shell that are made of calcium carbonate.

Hope this helps :)
5 0
3 years ago
What is the balanced net precipitation reaction for BaCl2 and KOH?
Dmitrij [34]
BaCl2 reacts with KOH forming KCl which is a salt and Ba(OH)2 which is the precipitate.
The initial UNBALANCED equation expressing this reaction would be:
BaCl2 + KOH .............> KCl + Ba(OH)2
Now, we need to balance this equation:
we have two moles of Cl as reactants and one mole only as product. Therefore, we will multiply the KCl in the product by 2 and the KOH in the reactants by 2.
This will balance the equation as follows:
BaCl2 + 2KOH ......> 2KCl + Ba(OH)2

Noticing this equation, we will find that:
The precipitate was formed due to the combination of the Ba2+ ion with 2 OH- ions as follows:
Ba2+ + OH- ............> Ba(OH)2
7 0
4 years ago
How much 10% solution and how much 45% solution should be mixed together to make 100 gallons of 25% solution?
Gnoma [55]
       x + y = 100

0.10x + 0.45 y =25

eliminate

x + y = 100
x  + 4.5 y = 250

-3.5 y = -150
y = 42.85
x = 57.15

hope this helps



5 0
3 years ago
Read 2 more answers
Consider a simple reaction in which a reactant AA forms products: A→productsA→products What is the rate law if the reaction is z
levacccp [35]

Answer :

The rate law expression for zero order reaction will be:

Rate=k[A]^0

The rate law expression for first order reaction will be:

Rate=k[A]^1

The rate law expression for second order reaction will be:

Rate=k[A]^2

Zero order reaction : There is no affect on the rate law.

First order reaction : The rate law becomes doubled.

Second order reaction : The rate law becomes quadrupled.

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given reaction is:

A\rightarrow Products

The rate law expression for zero order reaction will be:

Rate=k[A]^0

The rate law expression for first order reaction will be:

Rate=k[A]^1

The rate law expression for second order reaction will be:

Rate=k[A]^2

Now we have to determine that if doubling of the concentration of A then the rate of reaction will be:

As we know that the zero order reaction does not depend on the concentration of reactant. So, there is no affect on the rate law.

As we know that the first order reaction depend on the concentration of reactant. So, the rate law becomes doubled.

As we know that the second order reaction depend on the concentration of reactant. So, the rate law becomes quadrupled.

5 0
4 years ago
Which of he following is a secondary alkanol?
hodyreva [135]

Answer: Thus CH_3CH(OH)CH_3 is a secondary alkanol.

Explanation:

Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.

Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: CH_3CH_2CH_2OH and CH_3CH_2CH_2CH_2OH

Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example: CH_3CH(OH)CH_3

Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: C(CH_3)_3OH

Thus CH_3CH(OH)CH_3 is a secondary alkanol.

5 0
3 years ago
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