What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
2 answers:
<span>it is 3/6 = 0.5 mol/kg of solvent i.e. 0.5 molal <span>solution</span></span>
Answer: 0.5 m
Explanation:
Molality : It is defined as the number of moles of solute present per kg of solvent
Formula used :

where,
n= moles of solute
Moles of glucose = 3 moles
= weight of solvent (water) in g = 6 kg = 6000 g (1kg=1000g)
Now put all the given values in the formula of molality, we get

Therefore, the molality of solution will be 0.5 mole/kg.
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