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Andreas93 [3]
3 years ago
5

What is the molality of a solution that has 3 mol of glucose in 6 kg of water?

Chemistry
2 answers:
Cloud [144]3 years ago
4 0
<span>it is 3/6 = 0.5 mol/kg of solvent i.e. 0.5 molal <span>solution</span></span>
Rudik [331]3 years ago
3 0

Answer: 0.5 m

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

Molality=\frac{n\times 1000}{W_s}

where,

n= moles of solute

Moles of glucose = 3 moles

W_s = weight of solvent (water) in g  = 6 kg = 6000 g   (1kg=1000g)

Now put all the given values in the formula of molality, we get

Molality=\frac{3moles\times 1000}{6000g}=0.5mole/kg

Therefore, the molality of solution will be 0.5 mole/kg.

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An liquid's mass is 79.6 g. A student measures the volume to be 42.5mL. What is the density of the liquid?
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