Question

A particle with charge -5 C initially moves at v = (1.00 i^ + 7.00 j^ ) m/s. If it encounters a magnetic field B =80 Tkˆ, find the magnetic force vector on the particle.

Answer 1

Answer:

The magnetic force is  $\= F = 400\r j + 2800\r i$

Explanation:

From the question we are  told that

  The  charge is  $q = -5C$

  The  velocity is  $v = (1.00\ \r i + 7.00 \ \r j )\ m/s$

   The  magnetic field is  $B = 80 \r k \ \ T$

Generally the magnetic force is mathematically represented as

        $\= F = q \= v \ \ X \ \ \= B$

=>     $\= F = -5 (1.0 \r i + 7.0 \r j ) \ \ X \ \ 80 \r k$

=>    $\= F = -5.0 \r i + 35\r j \ \ \ X \ \ 80\r k$

=>  $\= F = 400\r j + 2800\r i$    N/B - Applied cross - product of unit vector