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2 years ago

With the aid of a string, a gyroscope is accelerated from rest to 16 rad/s in 0.40 s. what is its angular acceleration in rad/s2

Physics

1 answer:

vovikov84 [41]2 years ago

4 0

Angular acceleration = (change in angular speed) / (time for the change)

Change in angular speed = (ending speed) minus (starting speed)

Change in angular speed = (16 rad/s) - (zero) = 16 rad/s .

Angular acceleration = (16 rad/s) / (0.4 s)

(Average) angular acceleration = 40 rad/s²

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Answer:

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Explanation:

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As we know that

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m = Fc × R ÷ V^2

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Fc = 34.652 kN = 34652 N

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V = speed = 15.67 m/s

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m = 34652 × 24.98 ÷ 15.67^2

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2 years ago

Manuel is holding a 5 kg box. How much force us the box exerting on him? in what direction

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3 years ago

A 1.20 kg water balloon will break if it experiences more than 530 N of force. Your 'friend' whips the water balloon toward you

soldi70 [24.7K]

Answer:

t = 0.029s

Explanation:

In order to calculate the interaction time at the moment of catching the ball, you take into account that the force exerted on an object is also given by the change, on time, of its linear momentum:

$F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}$ (1)

m: mass of the water balloon = 1.20kg

Δv: change in the speed of the balloon = v2 - v1

v2: final speed = 0m/s (the balloon stops in my hands)

v1: initial speed = 13.0m/s

Δt: interaction time = ?

The water balloon brakes if the force is more than 530N. You solve the equation (1) for Δt and replace the values of the other parameters:

$|F|=|530N|= |m\frac{v_2-v_1}{\Delta t}|\\\\|530N|=| (1.20kg)\frac{0m/s-13.0m/s}{\Delta t}|\\\\\Delta t=0.029s$

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3 years ago

To store stacks of clean plates, a cafeteria uses a closed cart with a spring-loaded shelf inside. Customers can take plates off

ruslelena [56]

The answer for the following problem is mentioned below.

The option for the question is "A" approximately.

Therefore the elastic potential energy of the string is 20 J.

Explanation:

Given:

Spring constant (k) = 240 N/m

amount of the compression (x) = 0.40 m

To calculate:

Elastic potential energy (E)

We know;

According to the formula;

E = $\frac{1}{2}$ × k × x × x

E = $\frac{1}{2}$ × k ×(x)²

where;

E represents the elastic potential energy

K represents the spring constant

x represents amount of the compression in the string

So therefore,

Substituting the values in the above formula;

E = $\frac{1}{2}$ × 240 × (0.40)²

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E = $\frac{1}{2}$ × 38.4

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2 years ago

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