Answer : The mass of aluminium (Al) is 0.413 g
Solution : Given,
Volume of
at STP = 513 ml = 0.513 L ( 1 L = 1000 ml )
Molar mass of aluminium = 26.98 g/mole
First we have to calculate the moles of
.
At STP,
1 mole occupies 22.4 L volume
now, 0.513 L gives
moles of ![H_{2}(g)](https://tex.z-dn.net/?f=H_%7B2%7D%28g%29)
The moles of
= 0.0229 moles
The Net balanced chemical reaction is,
![2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)](https://tex.z-dn.net/?f=2Al%28s%29%2B6HCl%28aq%29%5Crightarrow%202AlCl_3%28aq%29%2B3H_2%28g%29)
From the balanced chemical reaction, we conclude that
2 moles of Aluminium (Al) produces 3 moles of hydrogen gas
Now the number of moles of aluminium required in 0.0229 moles of hydrogen gas =
= 0.0153 moles
Now we have to calculate the mass of aluminium.
Mass of aluminium = number of moles × Molar mass = 0.0153 moles × 26.98 g/mole = 0.413 g
The mass of aluminium required is 0.413 g.
Ans
The field of forensic science is subject to questions that can be answered by science
We are given the chemical reaction and the amount of fuel used for the process. We use these data together with the molar masses to obtain what is asked. We do as as follows:
100 g C8H18 ( 1 / 114.33) ( 16 / 2 ) = 6.9973 mol CO2 produced
Answer:
3
Explanation:
metallic oxides are basic in nature.
The answer to the question:
The names of all binary compounds, both ionic and molecular,
end in the letters ____
Is:
-
ide
The names of all the binary compounds, both the molecular
and ionic, end in the letters –ide.