There are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated by using the following formula:
molarity = no. of moles / volume
According to this question, a volume of 2300 mL solution is contained in 0.68 M MgSO4. The number of moles is calculated as follows:
no of moles = 0.68M × 2.3
no. of moles = 1.56
Therefore, there are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.
Learn more about moles at: brainly.com/question/12127540
Answer:
The volume of the gas is 0.015 m^3.
Explanation:
mass, m = 32 g
Temperature, T = 45 °C = 45 + 273 = 318 K
Pressure, P = 728 mm of hg = 0.728 x 13.6 x 1000 x 9.8 = 97027.84 Pa
Atomic mass = 4 x 12 + 10 x 1 = 58 g
Use the ideal gas equation
Let the volume is V.
P V = n R T
Answer:
False
Explanation:
Glucose is a substrate which undergoes various chemical reactions in the mitochondria to produce ATP, which is the universal energy carrier.
There are 67.6 ounces in a 2-liter soda.
The chemical equation of this reaction is: Fe + 2HCl -> FeCl2 + H2.
You can see that for 1mol of Fe you get 1mol of FeCl2. So you need 4mol of Fe to make 4mol of FeCl2.
