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mina [271]
4 years ago
8

What is the nature of this chlorine ion?

Chemistry
2 answers:
statuscvo [17]4 years ago
8 0
<span>The chlorine anion is a Lewis base.
The chlorine anion is a donor of electronic pair:

Cl</span>⁻ + H⁺ → HCl
PIT_PIT [208]4 years ago
3 0
As chlorine has seven electrons in its outer most shell so to complete its octet it has to gain an electron and when it gain an electron it will become an anion that is negatively charged
 so in my opinion and what a conclude is that the option B is correct for the above statement
You might be interested in
why is the term "ionic" used when describing compounds formed from a metal element and a nonmetal element?
nordsb [41]
Ionic compounds form when metals transfer valence electrons to nonmetals. Ionic compounds exist as crystals rather than molecules.
8 0
2 years ago
List all orbitals from 1s through 5s according to increasing energy for multielectron atoms. rank orbitals from smallest to larg
GaryK [48]

Answer:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s

Explanation:

You can predict the order of orbital energies by constructing a diagram as shown below.

Follow the arrows to get the orbitals in order of increasing energy.

The order is

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s

3 0
3 years ago
Which of the following equations are balanced?
Law Incorporation [45]
A: 2H₂ + O₂ → 2H₂O

    H: 4            H:4
    O: 2           O: 2

The equation is balanced.

B. 2S + 3O₂ → 2SO₃

     S: 2             S: 2
     O: 6            O: 6

The equation is balanced.

C. Li + Cl₂ → LiCl

     Li: 1          Li: 1
    Cl: 2          Cl: 1

The equation is not balanced.

    2Li + Cl₂ → 2LiCl

    Li: 2            Li: 2
    Cl: 2           Cl: 2

D: 2K + 2H₂O → H₂ + 2KOH

    K: 2                 K: 2
    H: 4                 H: 4
    O: 2                 O: 2

The equation is balanced.

E: 2Fe + Cu(NO₃)₂ → 2Cu + Fe(NO₃)₂

    Fe: 2                       Fe: 1
    Cu: 1                      Cu: 2
      N: 2                        N: 2
      O: 6                        O: 6

The equation is not balanced.

2Fe + 2Cu(NO₃)₂ → 2Cu + 2Fe(NO₃)₂

Fe: 2                        Fe: 2
Cu: 2                       Cu: 2
  N: 4                         N: 4
  O: 12                       O: 12

The following equations that are balanced are A, B, and D.
6 0
3 years ago
Initially, a particular sample has a total mass of 200 grams and contains 128 x 1010 radioactive nuclei. These radioactive nucle
lubasha [3.4K]

Explanation:

Formula to calculate how many particles are left is as follows.

              N = N_{0} (\frac{1}{2})^{l}

where,     N_{0} = number of initial particles

                              l = number of half lives

As it is given that number of initial particles is 128 \times 10^{10} and number of half-lives is 3.

Hence, putting the given values into the above equation as follows.

               N = N_{0} (\frac{1}{2})^{l}

                    = 128 \times 10^{10}(\frac{1}{2})^{3}

                    = 16 \times 10^{10}

or,                    1.6 \times 10^{11}

Thus, we can conclude that 1.6 \times 10^{11} particles of radioactive nuclei remain in the given sample.

In five hours we've gone through 5 half lives so the answer is:

particles

8 0
3 years ago
Twh-bmyd-aer<br> please j.o.i.n...
BartSMP [9]

Explanation:

ok will do

3 0
3 years ago
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