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Stolb23 [73]
3 years ago
11

Use your knowledge of valence electrons and how they affect bonds to figure out how carbon (Group 14) and oxygen (Group 16)

Chemistry
1 answer:
kenny6666 [7]3 years ago
5 0

Answer: D

Explanation:

O=C=O

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Inessa05 [86]

Answer: The electron arrangement for gallium is:

Ar 3d10 4s2 4p1

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What's the equation for the reaction of Trifluoro bromide with Ammonia gas. ( brainliest assured )​
sp2606 [1]

Answer:

Ammonium bromide can be prepared by the direct action of hydrogen bromide on ammonia. It can also be prepared by the reaction of ammonia with iron(II) bromide or iron(III) bromide, which may be obtained by passing aqueous bromine solution over iron filings.

Explanation:

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3 years ago
how many grams of calcium chloride can be prepared from 60.4 G of calcium oxide and 69.0 G of hydrochloric acid and a double dis
Ksenya-84 [330]
Balanced equation: 
<span>CaO + 2 HCl --> CaCl2 + H2O </span>
<span>Calculate moles of each reactant: </span>
<span>60.4 g CaO / 56.08 g/mol = 1.08 mol CaO </span>
<span>69.0 g HCl / 36.46 g/mol = 1.89 mol HCl </span>

<span>Identify the limiting reactant: </span>
<span>Moles CaO needed to react with all HCl: </span>
<span>1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO </span>
<span>Because you have more CaO than that available, HCl is the limiting reactant. </span>

<span>Calculate moles and mass CaCl2: </span>
<span>1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2</span>
8 0
3 years ago
Why does beryllium lose electrons when forming ionic bonds,while sulfur gains electrons?
Nadya [2.5K]
Beryllium is a metal so it needs to loose electrons to have a full outer shell while sulfur is a non-metal so it needs to gain electrons to fill its outer shell.
8 0
3 years ago
What is the concentration in molarity of S2O32- (aq) in a solution prepared by mixing 150 mLmL of 0.149 MM Na2S2O3 (aq) with eno
Artist 52 [7]

Answer:

0.0890 M

Explanation:

Since the concentration of KCl is irrelevant in this case, the concentration of Na2S2O3 can be determined using a simple dilution equation:

C1V1 = C2V2, where C1 = 0.149 M, V1 = 150 mL, V2 = 250 mL

C2 = 0.149 x 150/250

                    = 0.089 M

To determine the concentration of  S2O32- (aq), consider the equation:

Na_2S_2O_3  => 2Na^+_{(aq)} + S_2O^2^-_3_{(aq)}

The concentration of Na2S2O3 and S2O32- (aq) is 1:1

Hence, the concentration in molarity of S2O32- (aq) is 0.089 M.

To 3 significant figures = 0.0890 M

7 0
3 years ago
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