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andrew-mc [135]
3 years ago
12

If the output current for the transformer is 1.8 A, find the input current.

Physics
2 answers:
MariettaO [177]3 years ago
8 0
3.16 B please put brainliest have a cheerful day!
God bless
AlexFray555
Iteru [2.4K]3 years ago
3 0
The answer is 3.16 B
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A freezer has a coefficient of performance of 4.1. You place 0.45 kg of water at 16°C in the freezer, which maintains its temper
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2 years ago
Describe a scientific method
laila [671]

The process of <u>scientific method</u> involves making hypotheses , driving predictions from them as logical consequences , and then carrying out experiments or empirical observations based on those predictions. A hypotheses is a conjecture , based on knowledge obtained while seeking  answers to the questions.

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3 years ago
If objects at the same distance suddenly decreased in mass the gravitational force between them would
inn [45]

Answer:

The Gravitational force would decrease

Explanation:

To calculate FG the formula is:

Fg=mg

if mass decreases then the gravitational force would decrease

5 0
3 years ago
The froghopper Philaenus spumarius is supposedly the best jumper in the animal kingdom. To start a jump, this insect can acceler
Kay [80]

Answer:

Part a)

v_f = 4 m/s

Part b)

t = 0.001 s

Part c)

d = 0.815 m

Explanation:

Part a)

As we know that initially the grass hopper is at rest at the ground position

Now the acceleration is given as

a = 4000 m/s^2

distance of the legs that it stretched is given as

s = 2.0 mm

so we have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(4000)(0.002)

v_f = 4 m/s

Part b)

time taken to reach this speed is given as

v_f - v_i = at

4 - 0 = 4000 t

t = 0.001 s

Part c)

as the grass hopper reach the maximum height its final speed would be zero

so we will have

v_f^2 - v_i^2 = 2 a d

0 - 4^2 = 2(-9.81) d

d = 0.815 m

5 0
3 years ago
The total surface area of the human body is 1.20 m2 and the surface temperature is 30∘C=303∘K. If the surroundings are at a temp
zalisa [80]

To solve this problem we must consider the expressions of Stefan Boltzmann's law for which the rate of change of the radiation of energy H from a surface must be

H = Ae\sigma T^4

Where

A = Surface area

e = Emissivity that characterizes the emitting properties of the surface

\sigma = Universal constant called the Stefan-Boltzmann constant (5.67*10^{-8}m^{-2}K^{-4})

T = Absolute temperature

The total heat loss would be then

Q = H_2 -H_1

Q =Ae\sigma T_2^4-Ae\sigma T_1^4

Q = Ae\sigma (T_2^4-T_1^4)

Q = (1.2)(1)(5.67*10^{-8})(303^4-280^4)

Q = 155.29J

Therefore the net rate of heat loss from the body by radiation is 155.29J

8 0
3 years ago
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