The answer would be B because humans cannot see electrons so we visualize the electrons due to the theory
The answer is A. Hope this helps!!!
Well, those are good ones. Now how about a <u><em>thermometer</em></u> to <em>measure the temperature</em> ?
Answer : The cell potential for this cell 0.434 V
Solution :
The balanced cell reaction will be,
![Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)](https://tex.z-dn.net/?f=Cu%28s%29%2B2Ag%5E%7B%2B%7D%28aq%29%5Crightarrow%20Cu%5E%7B2%2B%7D%28aq%29%2B2Ag%28s%29)
Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.
First we have to calculate the standard electrode potential of the cell.
![E^o_{[Cu^{2+}/Cu]}=0.34V](https://tex.z-dn.net/?f=E%5Eo_%7B%5BCu%5E%7B2%2B%7D%2FCu%5D%7D%3D0.34V)
![E^o_{[Ag^{+}/Ag]}=0.80V](https://tex.z-dn.net/?f=E%5Eo_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D%3D0.80V)
![E^o=E^o_{[Ag^{+}/Ag]}-E^o_{[Cu^{2+}/Cu]}](https://tex.z-dn.net/?f=E%5Eo%3DE%5Eo_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D-E%5Eo_%7B%5BCu%5E%7B2%2B%7D%2FCu%5D%7D)
![E^o=0.80V-(0.34V)=0.46V](https://tex.z-dn.net/?f=E%5Eo%3D0.80V-%280.34V%29%3D0.46V)
Now we have to calculate the concentration of cell potential for this cell.
Using Nernest equation :
![E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cu^{2+}][Ag]^2}{[Cu][Ag^+]^2}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7D%5Clog%20%5Cfrac%7B%5BCu%5E%7B2%2B%7D%5D%5BAg%5D%5E2%7D%7B%5BCu%5D%5BAg%5E%2B%5D%5E2%7D)
where,
n = number of electrons in oxidation-reduction reaction = 2
= ?
Now put all the given values in the above equation, we get:
![E_{cell}=0.46-\frac{0.0592}{2}\log \frac{(1.14)\times (1)^2}{(1)\times (0.15)}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3D0.46-%5Cfrac%7B0.0592%7D%7B2%7D%5Clog%20%5Cfrac%7B%281.14%29%5Ctimes%20%281%29%5E2%7D%7B%281%29%5Ctimes%20%280.15%29%7D)
![E_{cell}=0.434V](https://tex.z-dn.net/?f=E_%7Bcell%7D%3D0.434V)
Therefore, the cell potential for this cell 0.434 V
Answer:
When the polythene rod is rubbed with the woolen cloth, static electric charges move from the cloth and into the rod. The rod becomes negatively charged as negative charges move from the cloth and into the rod leaving the cloth positively charged as well.