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2 years ago

Which relationship between sample size and sampling error is correct? Question 36 options:

Physics

1 answer:

KengaRu [80]2 years ago

6 0

Answer: option B

Explanation: The sampling error also known as the marginal error is given mathematically as

Margin of error = critical value × (standard deviation/√n)

Where n = sample size

As we can see from this formulae, the only variable here is the margin of error and the sample size.

Hence margin of error = k/√n

Which implies that there is an inverse relationship between margin of error and sample size.

A large sample size gives a low margin of error while a small sample size gives a large margin of error.

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Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up

Mademuasel [1]

Answer:

V = 90.51 m/s

Explanation:

From the given information:

Initial speed (u) = 0

Distance (S) = 391 m

Acceleration (a) = 18.9 m/s²

Using the relation for the equation of motion:

v² - u² = 2as

v² - 0² = 2as

v² = 2as

$v = \sqrt{2as}$

$v = \sqrt{2*18.9*391}$

v = 121.57 m/s

After the parachute opens:

The initial velocity = 121.57 m/ss

Distance S' = 332 m

Acceleration = -9.92 m/s²

How fast is the racer can be determined by using the relation:

$V= \sqrt{v^2 + 2aS'}$

$V = \sqrt{121.57^2+ 2 (-9.92)(332)}$

V = 90.51 m/s

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2 years ago

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ser-zykov [4K]

Answer:

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3 years ago

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