Answer:
6.91 Hz
Explanation:
Volume of the cube
= (1.5 x 10⁻² )³m³
= 3.375 x 10⁻⁶ m³
mass of the cube
= 3.375 x 10⁻⁶ x 8920 ( 8.92 g / cm³ = 8920 kg/m³ )
m = 30.105 x 10⁻³ kg
Spring stretches by 2.65 x 10⁻² m due to a force of 1.5 N.
If k be the force constant
k x = F
K x2.65 x 10⁻² = 1.5
k = .566 x 10² N / m
Now frequency of oscillation for spring - mass system is given by
n = 
=
n = 6.91 Hz
Answer:
1 m = 3.28 ft
1 m^2 = 10.76 ft^2
1560 ft^2 / 10.76 ft^2 / m^2 = 145 m^2
Answer:
3.66m/s^2
Explanation:
First, we need to find the friction which is F=u*N.
After that, find the resultant force by substarcting the friction from the forward force.
Lastly,using the formula F=ma, substitute in the known values of F and m to find a