The distance traveled by the wood after the bullet emerges is 0.16 m.
The given parameters;
- <em>mass of the bullet, m = 23 g = 0.023 g</em>
- <em>speed of the bullet, u = 230 m/s</em>
- <em>mass of the wood, m = 2 kg</em>
- <em>final speed of the bullet, v = 170 m/s</em>
- <em>coefficient of friction, μ = 0.15</em>
The final velocity of the wood after the bullet hits is calculated as follows;

The acceleration of the wood is calculated as follows;

The distance traveled by the wood after the bullet emerges is calculated as follows;

Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.
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It depends when you look at a pichture it could possibly help.
In very very very round figures . . .
-- Jupiter is about 5.2 times as far from the sun as the earth is.
-- So when Jupiter and the EARTH are aligned in both orbits, Jupiter is about
(4.2) x (150 million kilometers) = 630 million kilometers
Time = (distance) / (speed)
The speed of light and radio is 300,000 km/second
Time = (630 million / 300 thousand)
<em>Time = 2,100 seconds</em>
That's 35 minutes.
Answer:
The answer to your question is:
Explanation:
Data
mass = 4.33 kg
E = 41.7 J
v = ?
Formula
Ke = (1/2)mv²
Clear v from the equation
v = √2ke/m
Substitution
v = √2(41.7)/4.33
v = 19.26 m/s Result