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Gelneren [198K]
2 years ago
11

One afternoon, they get together to play singles matches (one-on-one competitions).Every member of the club plays one match with

another member of the club, so twentymatches are held. In how many ways can this be arranged?
Mathematics
1 answer:
weeeeeb [17]2 years ago
3 0

Answer:

{40\choose 2}*{38\choose 2}*...*{2\choose 2}

Step-by-step explanation:

20 matches, so there is 40 players in the club.

First number too chole 2 first players for match you can do it in {40\choose 2}.

Now you have 38 players, becaus you chose 2. Now frim 38 player you can choose new 2 in {38\choose 2} ways. So and on... you will have ways to choose 20 matches in:

{40\choose 2}*{38\choose 2}*...*{2\choose 2}.

You might be interested in
What is the volume of the triangular prism? Round to the nearest tenth.
kramer

Answer:

the volume of the triangular prism is 1,185.6  in³

Step-by-step explanation:

To find the volume of these triangular prism, we will, first, find the area of the triangle then multiply by the length

Area of triangle = \frac{1}{2} × b×h

From the diagram ,the height of the triangle  is given to be 10.4 in and the base is given to be 12 in.

We will now proceed to insert the values into the formula;

                 Area of triangle  = \frac{1}{2} × b×h

                                              = \frac{1}{2} × 12×10.4

                                             

                                                = \frac{1}{2} × 124.8

                                                 =62.4

Area of triangle is 62.4 in²

From the diagram is given to be 19 in

Volume of triangular prism = area of triangular prism × l

                                              =62.4 in²   ×    19 in

                                              =1,185.6  in³

Therefore the volume of the triangular prism is 1,185.6  in³

                                           

                           

5 0
2 years ago
Cual es el factor de 10?
Katarina [22]

Answer:

The factors of 10 are 1, 2, 5, and 10.

Translation: Los factores de 10 son 1, 2, 5 y 10.

Step-by-step explanation:

1x10= 10

2x5= 10

8 0
3 years ago
If a track has 219 miles and takes 108 minutes to get there. Is the average speed 104 miles per hour
Tema [17]

Answer:

<em><u>122 miles per hour</u></em><em><u>.</u></em><em><u> </u></em>

Step-by-step explanation:

Time:108 min ÷60 =1.8 hours

Speed = distance /time = 219/1.8 =122 miles per hour.

Hope this helps..

8 0
3 years ago
Read 2 more answers
Which point would be a solution to the system of linear inequalities ?
brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

y\leq \frac{4}{3}x+5 ----> inequality A

y\geq -\frac{5}{2}x+5 ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y  of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

-1\leq \frac{4}{3}(0)+5

-1\leq5 ----> is true

Inequality B

-1\geq -\frac{5}{2}(0)+5

-1\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

3\leq \frac{4}{3}(0)+5

3\leq5 ----> is true

Inequality B

3\geq -\frac{5}{2}(0)+5

3\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

-6\leq \frac{4}{3}(-6)+5

-6\leq-3 ----> is true

Inequality B

-6\geq -\frac{5}{2}(-6)+5

-6\geq 20----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

-6\leq \frac{4}{3}(12)+5

-6\leq21 ----> is true

Inequality B

-6\geq -\frac{5}{2}(12)+5

-6\geq -25 ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0
3 years ago
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
3 years ago
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