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Gelneren [198K]
3 years ago
11

One afternoon, they get together to play singles matches (one-on-one competitions).Every member of the club plays one match with

another member of the club, so twentymatches are held. In how many ways can this be arranged?
Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0

Answer:

{40\choose 2}*{38\choose 2}*...*{2\choose 2}

Step-by-step explanation:

20 matches, so there is 40 players in the club.

First number too chole 2 first players for match you can do it in {40\choose 2}.

Now you have 38 players, becaus you chose 2. Now frim 38 player you can choose new 2 in {38\choose 2} ways. So and on... you will have ways to choose 20 matches in:

{40\choose 2}*{38\choose 2}*...*{2\choose 2}.

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34 &lt; 5x + 9 &lt; 44<br> Inequality
Ksivusya [100]

Answer:

5 < x < 7

Step-by-step explanation:

- Move all terms not containing  x  from the center section of the inequality.

25  <  5 x  <  35

- Divide each term in the inequality by  5 .

5 < 1x < 7

5 < x < 7

i hope this helps :)

5 0
3 years ago
What is 10and 1 half divided by 7 eights​
Lunna [17]

Answer:

12

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A retail outlet offers a retention bonus for each shopping season an employee remains with the company. Samuel's starting pay is
miv72 [106K]

Answer:

Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr.

Step-by-step explanation:

You know that Samuel's starting pay is $12.50/hr and for each season Samuel remains with the company, he receives a $0.35/hr raise.

Samuel's hourly rate after n seasons at the company will then be:

f(n)= 12.50 + 0.35*n

To determine the hourly rate after 18 seasons, you must replace the value n with 18:

f(18)= 12.50 + 0.35*18

Solving you get:

f(18)= 12.50 + 6.3

f(18)= 18.8

<u><em>Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr. </em></u>

6 0
3 years ago
HELP54465745653475vccbxdsztgfghdcdx
vredina [299]

Answer:

Solution is invalid

Step-by-step explanation:

Let the time when they will have the same water content be x hours

At x hours;

For the first tank, the content will be;

50 + 10x

For the second;

29 + 3x

Equating both, will give us x

29 + 3x = 50 + 10x

We will get x as a negative number here

Since number of hours can not be negative, the solution is invalid

4 0
3 years ago
Evaluate 3x^2 – 2xy - 4y^2
kykrilka [37]

 Evaluate for x=2,y=−3

3(22)−(2)(2)(−3)−4(−3)2

3(22)−(2)(2)(−3)−4(−3)2

= C. −12

 

3 0
3 years ago
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