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Gelneren [198K]
3 years ago
11

One afternoon, they get together to play singles matches (one-on-one competitions).Every member of the club plays one match with

another member of the club, so twentymatches are held. In how many ways can this be arranged?
Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0

Answer:

{40\choose 2}*{38\choose 2}*...*{2\choose 2}

Step-by-step explanation:

20 matches, so there is 40 players in the club.

First number too chole 2 first players for match you can do it in {40\choose 2}.

Now you have 38 players, becaus you chose 2. Now frim 38 player you can choose new 2 in {38\choose 2} ways. So and on... you will have ways to choose 20 matches in:

{40\choose 2}*{38\choose 2}*...*{2\choose 2}.

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Find the distance points p (3,6) and q (7,3) to the nearest tenth?
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<h3>Answer: 5</h3>

=========================================================

One method is to plot the points P(3,6) and Q(7,3) on the same xy grid.  Plot a third point R at (3,3). See the diagram below.

A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.

a^2+b^2=c^2

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9+16 = c^2

c^2 = 25

c = sqrt(25)

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This is the length of PQ

-----------------------------------

Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).

d = \text{Distance from P to Q}\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(3-7)^2+(6-3)^2}\\\\d = \sqrt{(-4)^2+(3)^2}\\\\d = \sqrt{16+9}\\\\d = \sqrt{25}\\\\d = 5\\\\

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