Answer:
Contradiction
Step-by-step explanation:
Suppose that G has more than one cycle and let C be one of the cycles of G, if we remove one of the edges of C from G, then by our supposition the new graph G' would have a cycle. However, the number of edges of G' is equal to m-1=n-1 and G' has the same vertices of G, which means that n is the number of vertices of G. Therefore, the number of edges of G' is equal to the number of vertices of G' minus 1, which tells us that G' is a tree (it has no cycles), and so we get a contradiction.
Answer:
14
Step-by-step explanation:
We can make this and equation
x • y = 1260
x = 3y +48
Our equation is
(3y +48)y = 1260
We get y = 14
Answer:
The value of x is 3
Step-by-step explanation:
∵ Quadrilateral ABCD is congruent to quadrilateral JKLM
∴ AB = JK and BC = KL
∴ CD = LM and AD = JM
∵ BC = 8x + 7
∵ KL = 31
∵ BC = KL
→ Equate their right sides
∴ 8x + 7 = 31
→ Subtract 7 from both sides
∵ 8x + 7 - 7 = 31 - 7
∴ 8x = 24
→ Divide both sides by 8 to find x
∴
= 
∴ x = 3
∴ The value of x is 3
Answer:
62
Step-by-step explanation:
well, we start by expressing the number:
a b
we understand that using the above expression, the value of the number is 10a + b
using the information in the question,
a = 3b (1)
and,
11b + 11a = 88 (2) (derived using 10a + b form)
hence, when substituting (1) into (2):
11b + 33b = 88
44b = 88
b = 2 (3)
sub (3) into (1)
a = 6
hence, the number is 62
Answer:
Step-by-step explanation:
1). Step 4:
[Since,
]
![x=\sqrt[3]{5\times 5\times 5\times 5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5Ctimes%205%5Ctimes%205%5Ctimes%205%7D)
Step 5:
![x=\sqrt[3]{(5)^3\times 5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%285%29%5E3%5Ctimes%205%7D)
![x=\sqrt[3]{5^3}\times \sqrt[3]{5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B5%7D)
2). He simplified the expression by removing exponents from the given expression.
3). Let the radical equation is,

Step 1:

Step 2:

Step 3:

Step 4:

4). By substituting
in the original equation.



There is no extraneous solution.