First convert from mi/h to ft/s. There are 5280 ft to 1 mi, and 3600 s to 1 h, so
36 mi/h = (36 mi/h) * (5280 ft/mi) * (1/3600 h/s) = 52.8 ft/s
Let <em>a</em> be the acceleration of the car. The car's speed at time <em>t</em> is
<em>v</em> = 52.8 ft/s + <em>a</em> <em>t</em>
so that after 5.4 s, it attains a speed of
<em>v</em> = 52.8 ft/s + (5.4 s) <em>a</em>
Recall that
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> is the car's initial velocity and ∆<em>x</em> is the distance it's traveled.
We have
(52.8 ft/s + (5.4 s) <em>a</em>)² - (52.8 ft/s)² = 2 <em>a</em> (595 ft)
Omitting units, this equation reduces to
(52.8 + 5.4 <em>a</em>)² - 52.8² = 1190 <em>a</em>
==> 29.16 <em>a</em>² - 619.76 <em>a</em> = 0
==> 29.16 <em>a</em> - 619.76 = 0
==> 29.16 <em>a</em> = 619.76
==> <em>a</em> ≈ 21.25 ft/s²
The wavelength was doubled, and its energy will be increased by 4 times.
looking at the formula
energy 
also, 
hence it is clear from above that energy is directly proportional to the square of the wavelength.
hence, The wavelength was doubled, and its energy will be increased by 4 times.
<h3>
What is Wavelength?</h3>
- The distance over which a periodic wave's shape repeats is known as the wavelength in physics.
- It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.
- The spatial frequency is the reciprocal of the wavelength. The Greek letter lambda is frequently used to represent wavelength.
- The term wavelength is occasionally used to describe modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.
To learn more about wavelength with the given link
brainly.com/question/13533093
#SPJ4
Answer:
yes; yes
Explanation:
Phases of the moon refers to the shapes of the moon due to the lit part of it visible from the Earth. On a new moon day, the moon comes between the sun and the earth such that the lit portion is not visible from the Earth. On a full moon day, the earth comes between the sun and the moon and the whole lit part is visible.
When one would view the earth from the moon, the earth would also be visible as going through the phases. The order would be reversed. Understand this with the following example, On a new moon day, the Earth would be visible completely lit from the moon. So it will be full Earth day on the moon. On a full moon day, the lit side of the Earth would be completely away and hence, from the moon, new earth would be there.
The answer is Density. The Density of the <span>glass is measured with bromoform and bromobenzene mixtures in a column. </span>Density measurement<span> is done using Density gradient </span>columns. It is a <span> temperature-controlled density </span>column<span> containing a </span>mixture<span> of b</span>romobenzene<span> and </span>bromoform.
Answer:
a=1.03 m/s²
Explanation:
given required
dist=22.1 cm a=?
m1=2.1 kg
m2=1.56 kg
m3=1.93 kg
g=9.8 m/s²
solution
there are three forces on this system so we can solve by using newton's second law as follows
t1,t2,and weight of are the only forces acted on the system,
if we take the system on the left mass m3
-m3a=t2-m3g
-1.93 kg×a=t2-1.93 kg×9.8 m/s²
-1.93 kg×a=t2-18.91 N................................ eq 1
take at the right mass m2
m2a=t2-m2×g
1.56 kg×a=t2-1.56 kg×9.8 m/s²
1.56 kg×a=t2-15.288 N...................................2
add the two equations simultaneously and then solve for a,
-1×(-1.93 kg×a=t2-18.91 N) multiply by -1 the first and add the two equations
1.56 kg×a=t2-15.288 N
3.49 kg×a=3.622 N
a=1.03 m/s²
