Answer:
The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.
Explanation:
Given:
The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1
The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1
The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1
Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1
I’m not really sure but I think it’s D type 1 lever
physical property is a characteristics of a pure substance that can be observed without changing the substance into someone else.
Answer:
8962.5 N
Explanation:
From fundamental kinematics equations, acceleration, a is given by 
where v is final velocity, u is initial velocity and t is time
We also know that force is a product of mass and acceleration of an object and substituting in the formula F=ma we obtain
where m is the mass of the body
Therefore, the force is 8962.5 N
The cat fell 1.0 m from the ground.
Using the formula
Here, 
Solving for t, the time it spent in the air is
The cat does not accelerate along the horizontal, so it has constant horizontal velocity. Since it strikes the floor 2.2 m from the table, then
