Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
Answer:
if I am right it is 12,600 words
Step-by-step explanation: 90 divided by 3 which is 30 420x30=12,600
Answer:
.47
Step-by-step explanation:
1/10= .1
0.0.47/.1=.47
-1 x .47=0.47
Answer:
RS=13
Step-by-step explanation:
RS+ST=RT
2w+1+w-1=18
3w=18
w=6
RS= 2w+1= 2(6)+1= 12+1= 13
Answer:
11196.15 km
Step-by-step explanation:
Consider the attached diagram
If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.
Using trigonometry
Cross multiply
|AB|X Tan 15 =3000
|AB| = 
=11196.15 km
Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km
