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MakcuM [25]
2 years ago
14

What is the citric acid concentration in a soda if it requires 32. 27 ml of 0. 0148 m naoh to titrate 25. 00 ml of soda?.

Chemistry
2 answers:
sveticcg [70]2 years ago
8 0

Answer:

soln

32.27ml-25.00

7.27 ÷ 0.0148

7248 answer

Rudiy272 years ago
7 0

Titration

citric acid: CH₃COOH, c = 1

caustic soda: NaOH  c = 1

V₁M₁c₁=V₂M₂c₂ (c = valence)

\tt 32.27\times 0.0148\times 1=25\times M_2\times 1\\\\M_2=0.019\:M

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<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})
  2. Multiply:                                                                                                             \displaystyle 18.9306 \ g \ F_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

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