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Rus_ich [418]
3 years ago
13

Power plants use specialized scrubbers to remove sulfur oxide gases. true or false.

Chemistry
2 answers:
Ostrovityanka [42]3 years ago
8 0
<h2>Answer:</h2>

The given statement is TRUE

<h2>Explanation:</h2>

Sulfur oxides (SOx) are compounds of sulfur and oxygen molecules. Sulfur dioxide (SO2) is the pre- dominant form found in the lower atmosphere. It is a colorless gas that can be detected by taste and smell. Scrubbers help to remove most of the sulfur oxides from the smoke stack exhaust of a power plant. In the scrubber, there is a water spray that produces a cloud of fine water droplets. The water is mixed with crushed limestone, which reacts with the sulfur and pulls it out of the exhaust

Usimov [2.4K]3 years ago
7 0
True. But it is not entirely fool proof.
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Answer:

European Union was on grand committee

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3 years ago
In the formula 5CaSO4 the total number of sulfur atoms present is a. 1. b. 5. c. 9. d. 20?
podryga [215]
The answer is b . (1*5=5)
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When the pressure on 2.5 liters of oxygen is decreased from 2.0 atm to 1.0 atm, the volume of the gas
uranmaximum [27]

Answer:

volume of the gas is 5.0L

Explanation:

Using Boyle's law that state the pressure of a gas is inversely proportional to volume of it occupies when temperature is constant, it is possible to write:

P₁V₁ = P₂V₂

<em>Where P is pressure, V is volume and 1 and 2 are initial and final states.</em>

<em />

If initial volume is 2.5L, initial pressure is 2.0atm and 1.0atm is final pressure, final volume is:

2.0atm*2.5L = 1atm V₂

5.0L = V₂

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5 0
3 years ago
You are burning wood to heat water for your industrial process. What is the mass of wood required to raise the temperature of 10
natta225 [31]

Answer:

18,8kg of wood

Explanation:

The energy you need to to raise the temperature of 1000 kg of water from 25.0 to 100.0 °C is:

q = C×m×ΔT

Where: q is heat, C is specific heat of water (4,184J/g°C), m is mass in grams (1000x10³g), and ΔT is 100,0°C - 25,0°C = 75,0°C

Replacing:

q = 4,184J/g°C×1000x10³g×75,0°C

<u><em>q = 3,14x10⁸ J of heat are required</em></u>

<u><em /></u>

Now, if the heating value of dry wood is 16,72 MJ/kg = 16,72x10⁶ J/kg, mass of wood required is:

3,14x10⁸J × (1kg / 16,72x10⁶ J) = <em>18,8 kg of wood are required</em>

<em></em>

I hope it helps!

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3 years ago
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