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3 years ago

Can someone help me in this? a^2-ab-b-1

Mathematics

1 answer:

zheka24 [161]3 years ago

7 0

Answer:

(a + 1) (a − b − 1)

Step-by-step explanation:

I assume you're trying to factor the expression? If so, use quadratic formula to find the roots.

a = [ -(-b) ± √((-b)² − 4(1)(-b−1)) ] / 2(1)

a = [ b ± √(b² + 4b + 4) ] / 2

a = [ b ± (b + 2) ] / 2

a = -1 or b + 1

(a − (-1)) (a − (b + 1))

(a + 1) (a − b − 1)

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Can anyone help me ?

taurus [48]

Answer:

66,6% = ⅔

33,3% = ⅓

85% = 17⁄20

80% = ⅘

75% = ¾

90% = 9⁄10

20% = ⅕

10% = ⅒

Step-by-step explanation:

To convert from a fraction to a percentage, divide both the denominator and numerator to get a decimal point, then move the decimal point twice to the right, then attach the percentage symbol:

⅒ = 0,1 = 10%

⤻⤻

⅕ = 0,2 = 20%

⤻⤻

9⁄10 = 0,9 = 90%

⤻⤻

¾ = 0,75 = 75%

⤻⤻

⅘ = 0,8 = 80%

⤻⤻

17⁄20 = 0,85 = 85%

⤻⤻

_ _

⅓ = 0,3 = 33,3%

⤻⤻

_ _

⅔ = 0,6 = 66,6

All those bars above those digits are what are known as bar notation, indicating that digits repeat.

I am joyous to assist you anytime.

6 0

3 years ago

Find the value of x in the isosceles trapezoid below?

galina1969 [7]

Answer:

x = 31

Step-by-step explanation:

The sides of an isosceles trapezoid are the same length, so ...

5x -32 = 2x +61

3x = 93 . . . . . . . . add 32-2x

x = 31 . . . . . . . . . . divide by 3

6 0

3 years ago

After Lynda's initial client assessment, she has noted that her client will require inventory management to avoid out-of-stock s

Gelneren [198K]

Answer:

Most commonly seen in the consumer goods industry

6 0

2 years ago

(1 point) (a) Find the point Q that is a distance 0.1 from the point P=(6,6) in the direction of v=⟨−1,1⟩. Give five decimal pla

natima [27]

Answer:

following are the solution to the given points:

Step-by-step explanation:

In point a:

$\vec{v} = -\vec{1 i} +\vec{1j}\\\\|\vec{v}| = \sqrt{-1^2+1^2}$

$=\sqrt{1+1}\\\\=\sqrt{2}$

calculating unit vector:

$\frac{\vec{v}}{|\vec{v}|} = \frac{-1i+1j}{\sqrt{2}}$

the point Q is at a distance h from P(6,6) Here, h=0.1

$a=-6+O.1 \times \frac{-1}{\sqrt{2}}\\\\= 5.92928 \\\\b= 6+O.1 \times \frac{-1}{\sqrt{2}} \\\\= 6.07071$

the value of Q= (5.92928 ,6.07071 )

In point b:

Calculating the directional derivative of $f (x, y) = \sqrt{x+3y}$ at P in the direction of $\vec{v}$

$f_{PQ} (P) =\fracx{f(Q)-f(P)}{h}\\\\$

$=\frac{f(5.92928 ,6.07071)-f(6,6)}{0.1}\\\\=\frac{\sqrt{(5.92928+ 3 \times 6.07071)}-\sqrt{(6+ 3\times 6)}}{0.1}\\\\= \frac{0.197651557}{0.1}\\\\= 1.97651557$

$\vec{v} = 1.97651557$

In point C:

Computing the directional derivative using the partial derivatives of f.

$f_x(x,y)= \frac{1}{2 \sqrt{x+3y}}\\\\ f_x (6,6)= \frac{1}{2 \sqrt{22}}\\\\f_x(x,y)= \frac{1}{\sqrt{x+3y}}\\\\ f_x (6,6)= \frac{1}{\sqrt{22}}\\\\f_{(PQ)}(P)= (f_x \vec{i} + f_y \vec{j}) \cdot \frac{\vec{v}}{|\vec{v}|}\\\\= (\frac{1}{2 \sqrt{22}}\vec{i} + \frac{1}{\sqrt{22}} \vec{j}) \cdot \frac{-1}{\sqrt{2}}\vec{i} + \frac{1}{\sqrt{2}} \vec{j}$

4 0

3 years ago

Need help with this shape

NISA [10]

It is a quadrilateral

4 0

3 years ago