Answer:
no
Step-by-step explanation:
x+14=x14
Answer:
9) 128
10) 78
11) 31
12) 148
Step-by-step explanation:
9) we know that the segment across from the angle 48° is double the angle.
48 · 2 = 96
The segments around the circle should all add up to 360 so we add the two segments we know to find the unknown segment.
136 + 96 = 232
360 - 232 = 128
The answer for 9 is 128.
10)
61 + 80 = 141
180 - 141 = 39
39 * 2 = 78
The answer for question 10 is 78.
11)
236 + 62 = 298
360 - 298 = 62
62 ÷ 2 = 31
The answer for question 11 is 31.
12)
50 · 2 = 100
100 + 112 = 212
360 - 212 = 148
The answer for question 12 is 148.
Answer: 0.2
Step-by-step explanation:
We know that , the probability density function for uniform distribution is given buy :-
, where x is uniformly distributed in interval [a,b].
Given : The time to process a loan application follows a uniform distribution over the range of 8 to 13 days.
Let x denotes the time to process a loan application.
So the probability distribution function of x for interval[8,13] will be :-

Now , the probability that a randomly selected loan application takes longer than 12 days to process will be :-
![\int^{13}_{12}\ f(x)\ dx\\\\=\int^{13}_{12}\dfrac{1}{5}\ dx\\\\=\dfrac{1}{5}[x]^{13}_{12}\\\\=\dfrac{1}{5}(13-12)=\dfrac{1}{5}=0.2](https://tex.z-dn.net/?f=%5Cint%5E%7B13%7D_%7B12%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B13%7D_%7B12%7D%5Cdfrac%7B1%7D%7B5%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B5%7D%5Bx%5D%5E%7B13%7D_%7B12%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B5%7D%2813-12%29%3D%5Cdfrac%7B1%7D%7B5%7D%3D0.2)
Hence, the probability that a randomly selected loan application takes longer than 12 days to process = 0.2
A.
Because negative multiplied by negative is positive
The matrix equation that represents this situation is
![\left[\begin{array}{ccc}3&2&0\\1&0&4\\3&1&1\end{array}\right]*\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}13.50\\16.50\\14.00\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%262%260%5C%5C1%260%264%5C%5C3%261%261%5Cend%7Barray%7D%5Cright%5D%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D13.50%5C%5C16.50%5C%5C14.00%5Cend%7Barray%7D%5Cright%5D%20)
Use technology to find the inverse of matrix A:
![A^{-1}= \left[\begin{array}{ccc}-\frac{2}{5}&-\frac{1}{5}&\frac{4}{5}\\ \frac{11}{10}&\frac{3}{10}&-\frac{6}{5}\\\frac{1}{10}&\frac{3}{10}&-\frac{1}{5}\end{array}\right]](https://tex.z-dn.net/?f=A%5E%7B-1%7D%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-%5Cfrac%7B2%7D%7B5%7D%26-%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B4%7D%7B5%7D%5C%5C%0A%5Cfrac%7B11%7D%7B10%7D%26%5Cfrac%7B3%7D%7B10%7D%26-%5Cfrac%7B6%7D%7B5%7D%5C%5C%5Cfrac%7B1%7D%7B10%7D%26%5Cfrac%7B3%7D%7B10%7D%26-%5Cfrac%7B1%7D%7B5%7D%5Cend%7Barray%7D%5Cright%5D%20)
Multiplying A inverse by B, we get the solution matrix
[tex]\left[\begin{array}{ccc}2.50\\3\\3.50\end{array}\right][\tex]