A diver shines a flashlight upward from beneath the water at an angle of 46.5 degrees to the vertical.
1 answer:
<span><span>θi</span>=<span>sin<span>−1</span></span>(μsin<span>θr</span>)
=<span>sin<span>−1</span></span>(1.33×sin46.5)
=74.7degrees</span>
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