4 years ago

Please help me. WILL GIVE BRAINLIEST

Mathematics

2 answers:

AnnZ [28]4 years ago

6 0

Answer:

third option

Step-by-step explanation:

Given that x = - 2 + $\sqrt{8}$ is a root

Complex roots always occur as conjugate pairs , thus

x = - 2 + $\sqrt{8}$ is a root then x = - 2 - $\sqrt{8}$ is a root

The required factor is then

(x - (- 2 - $\sqrt{8}$ ) )

Aloiza [94]4 years ago

3 0

Answer:

Step-by-step explanation:

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