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zlopas [31]
3 years ago
11

What's a good idea for a limiting reactant project

Chemistry
1 answer:
amid [387]3 years ago
7 0
Original Recipe
1 (18 1/4 ounce) Box devils food cake mix
1/2 cup vegetable oil
2 large eggs
Confectioners' Sugar (for rolling)

Directions:
Preheat oven to 350 degrees. Stir (by hand) cake mix, oil, and eggs- until dough forms. Dust with sugar and shape into 1 inch balls. Roll balls in sugar and place on ungreased cookie sheet. Bake 8-10 minutes. Remove from pan after one minute and put on cooling rack.
Cooking for 17 people
My original yield was 30 cookies.

17 cookies (1box cake mix/30 cookies)= .56 of a box= 1/2 box

17 cookies (1/2 cup oil/30 cookies)= .283 cups of oil= 1/4 cups

17 cookies (2 eggs/30 cookies)= 1.13 eggs= 1 egg
Percent Yeild
I was able to bake 24 cookies, with my original yeild being 30.


(24 cookies/30 cookies) x 100= 80% yeild
<span>Limiting Reactant Project
Fudge Crinkles</span>
By Autumn Gordon
Limiting Reactant
I have...
1 box of cake mix
48 oz or 6 cups of oil
12 eggs
Limiting is cake mix.
Left over is...
5.5 cups of oil
10 eggs<span>
</span>
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What is the pH of a solution with a concentration of 2.4 × 10-5 molar H3O+? Show, or explain, the work used to solve this proble
MrRissso [65]
pH=-log|H_{3}O^{+}|\\\\&#10;pH=-log2.4*10^{-5}=-(log2.4+log10^{-5})=-(0,38-5)=-(-4.62)\\\\&#10;pH=4.62
7 0
3 years ago
Read 2 more answers
EXTRA CREDIT
marin [14]

Answer:

\huge\boxed{\sf 36\ H\ atoms}

Explanation:

<u>Molecular formula from Glucose:</u>

C₆H₁₂O₆

<u>3 moles of Glucose:</u>

3C₆H₁₂O₆

In 1 mole of Glucose, there are 12 hydrogen atoms.

<u>In 3 moles:</u>

= 12 × 3

= 36 H atoms

\rule[225]{225}{2}

5 0
2 years ago
If water has no color, why does your hair get darker when water makes contact with it?
Simora [160]

Answer:

The water makes your individual hairs stick close together. ... When more light is absorbed by your wet hair, less light gets reflected back to your eyes. The result is that your hair appears darker than when it's dry.

6 0
3 years ago
Using your knowledge of reagents that react with alkenes, what would be a reagent that you could use to check and see if the hyd
igomit [66]

Answer:

An halogen addition reaction, particularly bromine addition, could be used to check if the hydrogenation has completed.

Explanation:

The aim is to find a way to check if the hydrogenation process of an alkene has completed. So the logic should be use a reaction that needs the participation of the double bound of the alkene, and therefore shouldn't take place in the process has finished.

A simple organic reaction is the halogen addition reaction, which occur between the halogen molecule and the double bond of the alkene. Basically, the pi electrons of the double bond attacks a relatively electrophilic halogen atom following a mechanism that leads to the addition of two halogen atoms to the double bond. As a consequence the alkene transforms into an haloalkane.

Also, a commonly used halogen is bromine, as it has a reasonable reactivity and it has red colour, which allows to monitor the progression of the reaction.

Taking all this in account, we can say that using a bromine addition reaction to the alkene it's a good option to check the completion of the hydrogenation.

Note that the bromine will react only if the double bond is present. So, if the hydrogenation has completed, the reaction won't occur. Using bromine will be the best option, as it is red coloured. That means that is we add bromine to an incomplete hydrogenation, as it will react with the alkene, the colour should disappear.

In other words, to check if the hydrogenation reaction has completed, we should add bromine and see what happens to the colour. If it doesn't change, then the hydrogenation reaction has completed.

3 0
3 years ago
En un experimento hacemos reaccionar 12 g de carbono con 32 g de oxígeno para formar dióxido de carbono. Razona si podemos saber
max2010maxim [7]

Answer:

La masa de óxido de carbono iv formado es 44 g.

Explanation:

En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.

En primer lugar, necesitamos escribir una ecuación química equilibrada.

C + O2 → CO2

De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.

Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?

Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.

Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g

5 0
3 years ago
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