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Valentin [98]
2 years ago
13

Consider the reaction hc2h3o2(aq) h2o(l) → h3o (aq) c2h3o2–(aq). Which species is the conjugate acid?a. C2h3o2-(aq)b. H2o(l)c. H

3o (aq)d. Hc2h3o2(aq)e. Two of these
Chemistry
1 answer:
saul85 [17]2 years ago
3 0

The species that is the conjugate acid is HC₂H₃O₂(aq). The correct option is d.

<h3>What are conjugate acid?</h3>

Conjugates acids are those acids which are made when an acid donates a proton to a base according to Bronsted Lowry theory.

In other words, we can say that it is an acid with hydrogen ion. An example is  water (base) reacting with an acid to form the hydronium ion (conjugate acid).

Thus, the correct option is d, HC₂H₃O₂(aq).

Learn more about conjugate acid

brainly.com/question/12883745

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A rectangle solid of unknown density is 5 m long two meters high and 4 meters wide. The mass of this solid is 300 grams. Find th
aksik [14]
D= M/V so, D=300/40 wich is 7.5 so D= 7.5g/m3
6 0
3 years ago
As you move across the period on the periodic table what pattern can be described about the electron configurations?
xeze [42]

Answer:

Elements in the same period have same number of electronic shell and electron is increased by one in every coming element with in same electronic shell.

Explanation:

Consider the second period of periodic table. This period consist of eight elements lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine and neon.

Electronic configuration of lithium:

Li₃ = [He] 2s¹

Electronic configuration of beryllium:

Be₄ = [He] 2s²

Electronic configuration of boron:

B₅ = [He] 2s² 2p¹

Electronic configuration of carbon:

C₆ = [He] 2s² 2p²

Electronic configuration of nitrogen:

N₇ = [He] 2s² 2p³

Electronic configuration of oxygen:

O₈ = [He] 2s² 2p⁴

Electronic configuration of fluorine:

F₉ = [He] 2s² 2p⁵

Electronic configuration of neon:

Ne₁₀ = [He] 2s² 2p⁶

All these elements present in same period having same electronic shell and number of electron increased by 1.

4 0
3 years ago
1 What is the total number of valence electrons in the Lewis structure of C104?
Lera25 [3.4K]
There are 32 valence electrons for the Lewis structure for ClO4

8 0
3 years ago
What would be the mass of a 33.5dm3 sample of O2 at STP?
liraira [26]

Answer:

• One mole of oxygen is equivalent to 16 grams.

→ But at STP, 22.4 dm³ are occupied by 1 mole.

{ \tt{22.4 \:  {dm}^{3}   \: \dashrightarrow \: 16 \: grams}} \\  { \tt{33.5 \:  {dm}^{3}  \:  \dashrightarrow \: ( \frac{33.5 \times 16}{22.4} ) \: grams}} \\  \\  \dashrightarrow \: { \boxed{ \tt{23.94 \: g \approx \: 24 \: grams}}}

7 0
3 years ago
Pls Help me I am stuck on this question.​
kolbaska11 [484]

Answer:

compound is the answer

4 0
3 years ago
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